现在我可以从属性文件中注入值:
@Value("${aaa.prop}")
public String someProp;
但我想要更多......
例如我有一些属性文件:
aaa.props=p1,p2,p3
aaa.props.p1=qwe
aaa.props.p2=asd
aaa.props.p3=zxc
我确信它包含属性aaa.props
,并且对其他属性一无所知。我希望使用以下代码来映射这些属性:
@Value ("${aaa.props}")
public Map<String, String> someProps;
导致someProps:{p1=qwe,p2=asd,p3=zxc}
答案 0 :(得分:5)
我为你构建了一个通用方法:通过过滤另一个地图来创建地图的工厂bean(毕竟属性是一种地图)。
这是工厂bean:
public class FilteredMapFactoryBean<V> extends
AbstractFactoryBean<Map<String, V>>{
private Map<String, V> input;
/**
* Set the input map.
*/
public void setInput(final Map<String, V> input){
this.input = input;
}
/**
* Set the string by which key prefixes will be filtered.
*/
public void setKeyFilterPrefix(final String keyFilterPrefix){
this.entryFilter = new EntryFilter<String, V>(){
@Override
public boolean accept(final Entry<String, V> entry){
return entry.getKey().startsWith(keyFilterPrefix);
}
};
}
public static interface EntryFilter<EK, EV> {
boolean accept(Map.Entry<EK, EV> entry);
}
/**
* If a prefix is not enough, you can supply a custom filter.
*/
public void setEntryFilter(final EntryFilter<String, V> entryFilter){
this.entryFilter = entryFilter;
}
private EntryFilter<String, V> entryFilter;
/**
* {@inheritDoc}
*/
@Override
public Class<?> getObjectType(){
return Map.class;
}
/**
* {@inheritDoc}
*/
@Override
protected Map<String, V> createInstance() throws Exception{
final Map<String, V> map = new LinkedHashMap<String, V>();
for(final Entry<String, V> entry : this.input.entrySet()){
if(this.entryFilter == null || this.entryFilter.accept(entry)){
map.put(entry.getKey(), entry.getValue());
}
}
return map;
}
}
这是一个带有一些示例用法的spring bean定义文件:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">
<!-- use System.getProperties() as input -->
<bean class="spring.test.FilteredMapFactoryBean" id="javaMap">
<property name="keyFilterPrefix" value="java." />
<property name="input" value="#{T(java.lang.System).getProperties()}" />
</bean>
<!-- use custom properties as input -->
<bean class="spring.test.FilteredMapFactoryBean" id="customMap">
<property name="keyFilterPrefix" value="hello" />
<property name="input">
<props>
<prop key="hello">Is it me you're looking for?</prop>
<prop key="hello.again">Just called to say: hello.</prop>
<prop key="hello.goodby">You say goodbye and I say hello</prop>
<prop key="goodbye.blue.sky">Did-did-did-did-you hear the falling bombs?</prop>
<prop key="goodbye.ruby.tuesday">Who could hang a name on you?</prop>
</props>
</property>
</bean>
</beans>
这是一个测试类:
public class Tester{
@SuppressWarnings("unchecked")
public static void main(final String[] args){
final ApplicationContext context =
new ClassPathXmlApplicationContext("classpath:spring/test/mapFactorybean.xml");
final Map<String, String> javaMap =
(Map<String, String>) context.getBean("javaMap");
print("java.", javaMap);
final Map<String, String> customMap =
(Map<String, String>) context.getBean("customMap");
print("hello.", customMap);
}
private static void print(final String prefix, final Map<String, String> map){
System.out.println("Map of items starting with " + prefix);
for(final Entry<String, String> entry : map.entrySet()){
System.out.println("\t" + entry.getKey() + ":" + entry.getValue());
}
System.out.println("");
}
}
输出符合预期:
Map of items starting with java.
java.runtime.name:Java(TM) SE Runtime Environment
java.vm.version:14.2-b01
java.vm.vendor:Sun Microsystems Inc.
java.vendor.url:http://java.sun.com/
java.vm.name:Java HotSpot(TM) Client VM
java.vm.specification.name:Java Virtual Machine Specification
java.runtime.version:1.6.0_16-b01
java.awt.graphicsenv:sun.awt.Win32GraphicsEnvironment
[... etc]
Map of items starting with hello.
hello.goodby:You say goodbye and I say hello
hello:Is it me you're looking for?
hello.again:Just called to say: hello.
答案 1 :(得分:2)
我恐怕你不能,直接。但你可以
ApplicationContextAware
并将ApplicationContext
设置为bean中的字段。@PostConstruct
方法调用context.getBean("${aaa.props}")
答案 2 :(得分:1)
您可以使用aaa.props={p1:'qwe',p2:'asd',p3:'zxc'}
。
属性文件:
@Value("#{${aaa.props}}")
private Map<String,String> someProps;
Java代码:
read
答案 3 :(得分:0)
你可以这样做: Maven依赖
<dependency>
<groupId>javax.annotation</groupId>
<artifactId>javax.annotation-api</artifactId>
<version>1.2</version>
</dependency>
添加导入。
import javax.annotation.Resource;
...
@Resource (name="propertiesMapName")
public Properties someProps;
在你的spring xml应用程序上下文中:
<util:properties id="propertiesMapName" location="classpath:yourFile.properties"/>
您将需要此命名空间
xmlns:util="http://www.springframework.org/schema/util"
http://www.springframework.org/schema/util
http://www.springframework.org/schema/util/spring-util-3.1.xsd
答案 4 :(得分:-1)
@ConfigurationProperties(prefix="my")
public class Config {
private List<String> servers = new ArrayList<String>();
public List<String> getServers() {
return this.servers;
}
}