Question

我有两个列表，需要检查它们是否包含相同顺序的相同对象。

list1 = [object1 , object2 , object3]
list2 = [object1 , object2 , object3]
list3 = [object2 , object3 , object1]

比较列表list1和list2，结果应为true。

比较列表list1和list3，结果应为false。

编辑：示例列表示例：list = [[<object1 at 0x04130AB0>], [<object2 at 0x04130210>, <object3 at 0x04130A10>]]

Answer 1

基本==只会检查一个list中的每个元素是否等于另一个list中的相应元素。但是，根据lst = [[<object1 at 0x04130AB0>], [<object2 at 0x04130210>, <object3 at 0x04130A10>]]的示例，您正在尝试检查身份。具有不同身份的两个对象可以比较为“相等”，这取决于该类的定义。以下是==告诉您两个list包含相同顺序的相同对象的示例：

>>> import collections
>>> a = collections.Counter()
>>> b = collections.Counter()
>>> a is b
False
>>> l1 = [a, b]
>>> l2 = [b, a]
>>> l1 == l2
True
>>> class Person:
...     def __eq__(self, other):
...         return True
...
>>> a = Person()
>>> b = Person()
>>> a is b
False
>>> l1 = [a, b]
>>> l2 = [b, a]
>>> l1 == l2
True
>>> a = []
>>> b = []
>>> a is b
False
>>> l1 = [a, b]
>>> l2 = [b, a]
>>> l1 == l2
True
>>> a.append(0)
>>> l1 == l2
False

如果要检查相应的元素实际上是同一个对象（标识，而不是相等），则需要以某种方式手动比较标识，如下所示：

>>> import collections
>>> a = collections.Counter()
>>> b = collections.Counter()
>>> a is b
False
>>> l1 = [a, b]
>>> l2 = [b, a]
>>> all(x is y for x,y in zip(l1, l2))
False
>>> a = Person()
>>> b = Person()
>>> a is b
False
>>> l1 = [a, b]
>>> l2 = [b, a]
>>> all(x is y for x,y in zip(l1, l2))
False
>>> a = []
>>> b = []
>>> a is b
False
>>> l1 = [a, b]
>>> l2 = [b, a]
>>> all(x is y for x,y in zip(l1, l2))
False

Answer 2

简单，只需使用SELECT REGEXP_COUNT(employeename, 'L', 1, 'c') NumberOfL, employeename FROM employee来共同编制两个列表。如果两个列表具有相同的元素并且应该以相同的顺序放置，那么这应该返回==，否则返回True

False

实现上述逻辑的函数应该是，

list1 == list2

例如：

def check_lists(list1, list2):
    return list1 == list2

Answer 3

假设T＆C在身份平等方面的身份很重要。

def check_id(li1, li2):
    return [id(o) for o in li1] == [id(o) for o in li2]

如何检查两个列表是否具有相同顺序的相同对象？

3 个答案: