Question

当我尝试创建一个新的Conversation项时，Sequelize会返回一个id: null的对象，尽管数据库中有一个有效的id。如何让Sequelize将最后插入的id返回给新创建的项？

Conversation.create({
  type: 'private',
  createdBy: 1,
}).then(conversation => {
  reply(conversation);
});

将返回

{
  "type": "conversations",
  "id": null,
  "createdBy": 1,
  "created_at": "2016-03-18T01:47:48.000Z"
}

我的代码：

const Conversation = model.define('Conversation', {
  id: {
    type: Sequelize.INTEGER,
    primaryKey: true,
  },
  type: {
    type: Sequelize.ENUM,
    values: ['private', 'group'],
    validate: {
      isIn: ['private', 'group'],
    },
  },
  createdBy: {
    type: Sequelize.INTEGER,
    field: 'created_by',
  },
}, {
  tableName: 'conversations',
  timestamps: true,
  createdAt: 'created_at',
  updatedAt: false,
  getterMethods: {
    type: () => 'conversations',
  },
});

const User = model.define('User', {
  id: {
    type: Sequelize.INTEGER,
    primaryKey: true,
  },
  firstName: {
    type: Sequelize.STRING,
    field: 'first_name',
    allowNull: false,
  },
  lastName: {
    type: Sequelize.STRING,
    field: 'last_name',
    allowNull: true,
  },
  email: {
    type: Sequelize.STRING,
    allowNull: false,
  },
  profileImg: {
    type: Sequelize.STRING,
    field: 'profile_img',
    allowNull: false,
  },
  password: Sequelize.STRING,
}, {
  tableName: 'users',
  timestamps: true,
  createdAt: 'created_at',
  updatedAt: 'updated_at',
  getterMethods: {
    type: () => 'users',
  },
});

Conversation.belongsToMany(User, {
  foreignKey: 'conversation_id',
  otherKey: 'user_id',
  through: 'conversation_user',
  timestamps: false,
});

User.belongsToMany(Conversation, {
  as: 'conversations',
  foreignKey: 'user_id',
  otherKey: 'conversation_id',
  through: 'conversation_user',
  timestamps: false,
});

Answer 1

哟需要将argc == 1放入id字段

autoIncrement: true

就个人而言，我建议跳过id: { type: Sequelize.INTEGER, primaryKey: true, autoIncrement: true, }列，因为sequalize会自动为你做并且效果很好。

希望它有所帮助：）

Answer 2

问题是我的MySQL版本（5.6而不是5.7），更新了它，现在我在承诺中获得了创建项目的ID。

id：在sequelize中创建新项目时为null

2 个答案: