我正在尝试使用JavaFX获取图像的一部分，但代码在import UIKit
class DataViewController: UIViewController {
@IBOutlet weak var myImageView: UIImageView!
var dataObject: String?
override func viewDidLoad() {
super.viewDidLoad()
autoreleasepool { () -> () in
self.myImageView.image = UIImage(contentsOfFile: dataObject!) // with "contentsOfFile:" the images are uncached...
}
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}
时失败。
以下是代码：
y = 1一切顺利，直到循环中的public static Image crop(Image src, int col, int row) {
PixelReader r = src.getPixelReader();
int sx = col * Grid.SIZE; // start x
int sy = row * Grid.SIZE; // start y
int ex = sx + Grid.SIZE; // end x
int ey = sy + Grid.SIZE; // end y
int rx = 0; // x to be written
int ry = 0; // y to be written
System.out.println(sx + ", " + sy + ", " + ex + ", " + ey);
WritableImage out = new WritableImage(Grid.SIZE, Grid.SIZE);
PixelWriter w = out.getPixelWriter();
for(int y = sy; y < ey; y++, ry++) {
for(int x = sx; x < ex; x++, rx++) {
int c = r.getArgb(x, y);
w.setArgb(rx, ry, c);
System.out.println(rx + ", " + ry + ", " + x + ", " + y);
}
}
return out;
}
变为1，然后发生这种情况：
y我不知道出了什么问题。我会提供任何其他信息。
答案 0 :(得分：1)
您开始获取索引越界异常，因为当您开始每个新行时，您并未将rx重置为0。
但是，如果您需要从Grid.SIZE Grid.SIZE src裁剪(col, row)，从public static Image crop(Image src, int col, int row) {
PixelReader r = src.getPixelReader();
PixelFormat<IntBuffer> pixelFormat = PixelFormat.getIntArgbInstance() ;
int[] pixels = new int[Grid.SIZE * Grid.SIZE];
r.getPixels(col * Grid.SIZE, row * Grid.SIZE, Grid.SIZE, Grid.SIZE, pixelFormat,
pixels, 0, Grid.SIZE);
WritableImage out = new WritableImage(Grid.SIZE, Grid.SIZE);
PixelWriter w = out.getPixelWriter();
w.setPixels(0, 0, Grid.SIZE, Grid.SIZE, pixelFormat,
pixels, 0, Grid.SIZE);
return out ;
}
开始，更简单（也可能表现更好）的方法是：
(col+1)*Grid.SIZE > src.getWidth()显然，如果(row+1)*Grid.SIZE > src.getHeight()或IllegalArgumentException，您可以在方法中检查并在需要时抛出var modal = UIkit.modal(".modalSelector");
if ( modal.isActive() ) {
modal.hide();
} else {
modal.show();
}
$('.modalSelector').on({
'show.uk.modal': function(){
console.log("Modal is visible.");
},
'hide.uk.modal': function(){
console.log("Element is not visible.");
}
});
，这将会失败。