Question

我正在尝试在Python中复制以下CURL命令（我正在尝试使用特定IP上的某些数据发出POST请求）：

curl -k --data "phonenr=a_number&smstxt=Test&Submit=SendSms" https://admin:pass@ip/txsms.cgi

其中ip是远程服务器的IP，admin:pass是所需的凭据。

此CURL命令正确执行，响应为200。

使用以下python代码，我收到：

httplib.InvalidURL: nonnumeric port: 'pass@91.195.144.248'

有谁能告诉我我做错了什么？

import urllib2 as urllib
from os.path import join as joinPath
from urllib import urlencode

# constant
APPLICATION_PATH = '/srv/sms_alert/'
ALERT_POINT_PATH = joinPath(APPLICATION_PATH, 'alert_contact')
URL_REQUEST_TIMEOUT = 42

SMS_BOX_URL = 'https://admin:pass@ip/txsms.cgi'

with open(ALERT_POINT_PATH, 'r') as alertContactFile:
    for line in alertContactFile:
        line = line.strip('\n')
        data = {
            'phonenr': line,
            'smstext': 'Test',
            'Submit': 'SendSms'
        }
        url_data = urlencode(data)
        url_data = url_data.encode('UTF-8')
        req = urllib.Request(SMS_BOX_URL, url_data)
        with urllib.urlopen(req) as response:
            print(response.read())

Answer 1

好的，看看你的导入，代码应该工作正常。问题是首先你要将urllib2作为urllib导入，然后从urllib导入urlencode，这样你就不会得到你想要的功能。

查看从urlib2 docs中检索到的以下代码：

链接：URLLIB2 documentation

import urllib
import urllib2

url = 'http://www.someserver.com/cgi-bin/register.cgi'
values = {'name' : 'Michael Foord',
          'location' : 'Northampton',
          'language' : 'Python' }

data = urllib.urlencode(values)
req = urllib2.Request(url, data)
response = urllib2.urlopen(req)
the_page = response.read()

祝你好运！

Answer 2

问题是身份验证（我们假设它的基本身份验证）不能像curl命令一样发送，urllib会将用户视为主机名以及＆＃39;之后的内容。：＆＃39;作为端口，这就是你有这个错误的原因，

您必须尝试使用以下凭据设置urllib开启器：

import urllib2 as urllib
SMS_BOX_URL = 'https://hostname/txsms.cgi'
# Prepare an authentication handler
auth_handler = urllib.HTTPBasicAuthHandler()
# Set your authentication Handler (catch the realm by parsing the authentication request with your navigator
auth_handler.add_password('realm', 'the realm of the authent', 'admin', 'pass')
opener = urllib.build_opener(auth_handler)
# Install your opener for later use
urllib.install_opener(opener)

# use it
url_data = urlencode(data)
url_data = url_data.encode('UTF-8')
req = urllib.Request(SMS_BOX_URL, url_data)
with urllib.urlopen(req) as response:
  print(response.read())

这应该有效，
开启者只需要实例化一次

ref

使用Python中的urllib模拟curl命令 - httplib.InvalidURL：nonnumeric port：

2 个答案: