httplib.InvalidURL:非数字端口:

时间:2013-01-24 00:19:59

标签: python file

我正在尝试编写一个脚本,检查是否存在多个网址:

import httplib

with open('urls.txt') as urls:
    for url in urls:
        connection = httplib.HTTPConnection(url)
        connection.request("GET")
        response = connection.getresponse()
        if response.status == 200:
            print '[{}]: '.format(url), "Up!"

但我收到了这个错误:

Traceback (most recent call last):
  File "test.py", line 5, in <module>
    connection = httplib.HTTPConnection(url)
  File "/usr/lib/python2.7/httplib.py", line 693, in __init__
    self._set_hostport(host, port)
  File "/usr/lib/python2.7/httplib.py", line 721, in _set_hostport
    raise InvalidURL("nonnumeric port: '%s'" % host[i+1:])
httplib.InvalidURL: nonnumeric port: '//globo.com/galeria/amazonas/a.html

怎么了?

3 个答案:

答案 0 :(得分:17)

这可能是一个简单的解决方案,在这里

connection = httplib.HTTPConnection(url)

您使用的是httpconnection,因此无需提供类似于http://iGyan.org的网址,但您需要提供iGyan.org

简而言之,从您的网址中删除http://https://,因为httplib正在考虑:作为端口号,并且端口号必须是数字,

希望这有帮助!

答案 1 :(得分:6)

httplib.HttpConnection在其构造函数中获取远程网址的hostport,而不是整个网址。

对于您的使用案例,使用urllib2.urlopen更容易。

import urllib2

with open('urls.txt') as urls:
    for url in urls:
        try:
            r = urllib2.urlopen(url)
        except urllib2.URLError as e:
            r = e
        if r.code in (200, 401):
            print '[{}]: '.format(url), "Up!"
        elif r.code == 404:
            print '[{}]: '.format(url), "Not Found!" 

答案 2 :(得分:0)

非数字端口:

解决方案:

http.client.HTTPSConnection(“ api.cognitive.microsofttranslator.com”)

从服务URL或端点中删除“ https:// ”,它将起作用。

https://appdotpy.wordpress.com/2020/07/04/errorsolved-nonnumeric-port/