Question

我希望将以下sql语句转换为sql alchemy

select c1.id, c1.repository, c1.branch, c1.failed_step, c1.stop_time
from completed_builds as c1
where c1.stop_time = (
    select max(c2.stop_time)
    from completed_builds as c2
    where c1.branch = c2.branch
    and c1.repository = c2.repository
)
and c1.repository in ('flex', 'mob', 'tv')
and c1.branch in ('stage', 'int')
order by c1.repository, c1.branch

这将输出具有最高stop_time值的唯一分支+存储库对。

非常感谢！

Answer 1

使用子查询添加过滤器。

subq = (db.query(CompletedBuilds.id, 
                 func.max(CompletedBuilds.stop_time).label(‘max_stop_time’)
                 CompletedBuilds.branch,
                 CompletedBuilds.repository)
       .subquery())

q = (db.query(CompletedBuilds)
    .join(subq, subq.id  == CompletedBuilds.id)
    .filter( subq.branch == CompletedBuilds.branch,
            subq.repository == CompletedBuilds.repository, 
            CompletedBuilds.repository.in_(‘flex’, ‘mob’, ‘tv’), 
            CompletedBuilds.branch.in_(‘stage’, ‘int’))
    .order_by(CompletedBuilds.repository, CompletedBuilds.branch))

将原始sql转换为sql炼金术ORM

1 个答案: