Question

问题：

如何以每个商品名称始终唯一的方式显示表单。我不想将表单重定向到新页面。

<?php 
$sqltable = mysql_query("SELECT * from TABLE");
?>

<form action="" method="post" onsubmit="window.location.reload()">
//output truncatted
<table>

<?php
while ($row = mysql_fetch_array($sqltable)) 
       {
        echo "<tr> ";
        echo "<td>" . $row[offername] . "</td>";
        echo "<td>" . $row[points] . "</td>";
        echo "<td><input type='submit' value='Purchase' name='offername'</td>";
       }
       echo "</tr> ";
?>

</table>
</form>

offername= offer1, offer2 , offer3, offer4, offerN
points   = 100  , 200    , 10     , 50    , xxx

期望的输出。

当使用offer1单击提交按钮时，应将其名称更改为offer1，其他商品名称也同样如此。或者，表格应提交给各自的要约名称。

Answer 1

这将创建一个输入元素作为数组。

<?php 
$sqltable = mysql_query("SELECT * from TABLE");
?>

<form action="" method="post" onsubmit="window.location.reload()">
//output truncatted
<table>

<?php
while ($row = mysql_fetch_array($sqltable)) 
       {
        echo "<tr> ";
        echo "<td>" . $row[offername] . "</td>";
        echo "<td>" . $row[points] . "</td>";
        echo "<td><input type='submit' value='Purchase' name='offername[]'></td>";
       }
       echo "</tr> ";
?>

</table>
</form>

//offername= offer1, offer2 , offer3, offer4, offerN
//points   = 100  , 200    , 10     , 50    , xxx

if(isset($_POST['offername'])){
    $offernameArr=$_POST['offername'];
    foreach($offernameArr as $key => $offername ){
        //your code goes here
    }
}

Answer 2

试试此代码

<?php
$sqltable = mysql_query("SELECT * from TABLE");

//offername= offer1, offer2 , offer3, offer4, offerN
//points   = 100  , 200    , 10     , 50    , xxx

if(isset($_POST['Purchase']) && $_POST['Purchase'] == 'Purchase'){  
    if(isset($_POST['offername']))
        echo 'Submitted offer name is '.$_POST['offername'][0];
    else
        echo 'No offers selected';
}
?>
<form action="" method="post" onsubmit="window.location.reload()">

<table>
<?php
while ($row = mysql_fetch_array($sqltable)) 
{
echo "<tr> ";
echo "<td>" . $row['offername'] . "</td>";
echo "<td>" . $row['points'] . "</td>";
echo "<td><input type='radio' name='offername[]' value='".$row['offername']."'></td>";
echo "</tr> ";
}
echo "<tr><td colspan='3'><input type='submit' value='Purchase' name='Purchase'></td></tr>";
?>
</table>
</form>

Answer 3

//form.php    


 <?php 
    $sqltable = mysql_query("SELECT * from TABLE");
if($_GET['offername']){
$offer = $_GET['offername'];
// now you have desired offer name in $offer you can fetch data from db with given offername in where clause and use here
}
    ?>

    <table>

    <?php
    while ($row = mysql_fetch_array($sqltable)) 
           {
            echo "<tr> ";
            echo "<td>" . $row['offername'] . "</td>";
            echo "<td>" . $row['points'] . "</td>";
            echo "<td><a href='form.php?offername=".$row['offername']."'><input type='submit' value='".$row['offername']."' name='submit'></a></td>";
           }
           echo "</tr> ";
    ?>

    </table>

PHP，显示表单

3 个答案: