PHP / HTML表单显示

时间:2016-07-28 01:57:07

标签: php html

有人能告诉我我做错了什么吗?代码运行正常,但输出的结果很奇怪。它给了我一个额外的专栏。

<?php
error_reporting(E_ALL); ini_set('display_errors', 1);
$serverName = "server\sqlexpress";
$connectionInfo = array("Database"=>"mine");
$conn = sqlsrv_connect($serverName, $connectionInfo);
if($conn === FALSE){
  die( print_r( sqlsrv_errors(), true));
}

$sql = 'SELECT id, name, age FROM names';
$records = sqlsrv_query($conn, $sql);

?>

<html>
<head>
    <meta charset="UTF-8">
    <title>Heath Data</title>
</head>
<body>
    <table width="600" border="1" cellspacing="1" cellpadding="1">
        <tr>
            <th>ID</th>
            <th>Name</th>
            <th>Age</th>
        </tr>


    <?php
    while ($employee = sqlsrv_fetch_array($records, SQLSRV_FETCH_ASSOC)){
        echo "<tr>";
        echo "<td>".$employee['id']."<td>";
        echo "<td>".$employee['name']."<td>";
        echo "<td>".$employee['age']."<td>";
        echo "<tr>";

    }
    ?>

    </table>
</body>

这是rersult: enter image description here

为什么要添加额外的列?

2 个答案:

答案 0 :(得分:3)

只需要终止标记

wrap_content

答案 1 :(得分:0)

<?php
error_reporting(E_ALL); ini_set('display_errors', 1);
$serverName = "server\sqlexpress";
$connectionInfo = array("Database"=>"mine");
$conn = sqlsrv_connect($serverName, $connectionInfo);
if($conn === FALSE)
{
die( print_r( sqlsrv_errors(), true));
}

$sql = 'SELECT id, name, age FROM names';
$records = sqlsrv_query($conn, $sql);

?>

<html>
<head>
<meta charset="UTF-8">
<title>Heath Data</title>
</head>
<body>
<table width="600" border="1" cellspacing="1" cellpadding="1">
    <tr>
        <th>ID</th>
        <th>Name</th>
        <th>Age</th>
    </tr>


<?php
while ($employee = sqlsrv_fetch_array($records, SQLSRV_FETCH_ASSOC)){
    echo "<tr>";
    echo "<td>".$employee['id']."<td>";
    echo "<td>".$employee['name']."<td>";
    echo "<td>".$employee['age']."<td>";
    echo "<tr>";

}
?>

</table>