Lua <eof>预计附近有&#39; print&#39;

时间:2016-03-12 12:55:16

标签: lua eof zerobrane

我在lua遇到了麻烦。

问题一: 每次我运行以下程序时,控制台都会告诉我:

  

&#39;端&#39;预期(关闭&#39;功能&#39;在第1行)靠近&#39; local&#39;

请注意我在所有大写评论中标记错误的详细信息

function m11()
    local inst = mc.mcGetInstance() -- controller instance
    local gcodeLineNbr = mc.mcCntlGetGcodeLineNbr(inst) -- get current Gcode line number
    local gcodeLineStr = mc.mcCntlGetGcodeLine(inst, gcodeLineNbr)  -- get current Gcode line


    function valFromLine(string, axis)
        local startPoint = string.find(string, axis) + 1
        local outputVal = ""
        local isNum = true
        while isNum do
            local num = string.sub(string, startPoint, startPoint)
            startPoint = startPoint + 1
            if num ~= " " then
                outputVal = outputVal .. num
            else
                isNum = false
            end
        end
        outputVal = tonumber(outputVal)
    end
    return outputVal

    --COMPILER HIGHLIGHTS FOLLOWING LINE AS LOCATION OF ERROR
    local gcodeLocX = valFromLine(gcodeLineStr, "X")
    local curLocX = mc.mcAxisGetPos(inst, 0)        -- get current X axis value
    local curLocY = mc.mcAxisGetPos(inst, 1)        -- get current Y axis value
    local curLocZ = mc.mcAxisGetPos(inst, 2)        -- get current Z axis value
    local curAngB = mc.mcAxisGetPos(inst, 4)        -- get current C axis value
    local curAngC = mc.mcAxisGetPos(inst, 5)        -- get current C axis value
    local toolOffset = mc.mcCntlGetToolOffset(inst, 2)  -- get tool offset for axis Z

    function rotateToolB()
        local comHypot = toolOffset * math.sin(angle)       -- get XY planar dist from C pivot to tool centre point
        local compDestinX = comHypot * math.sin(math.rad(90) - curAxisC + curLocX
    end
end
--END OF M11() FUNCTION SHOULD BE HERE

if (mc.mcInEditor() == 1) then
    m11()
end

我无法理解为什么期待m11()如此早地关闭。

问题二: 我在一个完全独立的文件中重写了valFromLine(),我得到了:

  

&#39; EOF&#39;预计在&#39; print&#39;

附近
function valFromLine(string, axis)
    local startPoint = string.find(string, axis) + 1
    local outputVal = ""
    local isNum = true
    while isNum do
        local num = string.sub(string, startPoint, startPoint)
        startPoint = startPoint + 1
        if num ~= " " then
            outputVal = outputVal .. num
        else
            isNum = false
        end
    end
  outputVal = tonumber(outputVal)
end
return outputVal

print(valFromLine("GO1 X254.348 Y1039.456 Z150.13 B90.23 C13 M11", "X"))

我认为我的结局是&#39;声明,我无法在任何代码示例中找到它们的错误。我现在完全失去了想法,请帮忙。感谢。

1 个答案:

答案 0 :(得分:2)

return outputVal行位置错误。将其移动到函数valFromLine中。 你不能在函数之外返回。

正确的:

function someFunction()
  -- do something
  local something = "something"
  return something
end

错误:

function someFunction()
  -- do something
  local something = "something"
end
return something

使用函数定义全局函数也不是很干净,使用本地函数。