Question

我列出了约90,000种产品和约2000家供应商。每个产品都应该获得一个独特的产品代码，我们公司以这种格式执行此操作：First 2 letters of the suppliers name, 5 digit suppliers number and a 5 digit product number in that group. 我需要能够在sql（首选项：MS ACCESS 2013）或SQL Server中执行此操作。

这就是我想要的：

product_code     suppliers_code       suppliers_name     product_name
PA0009100001     00091                Pardaen NV         product 1
PA0009100002     00091                Pardaen NV         product BB
PA0009100003     00091                Pardaen NV         product CC
HU1007300001     10073                Husqverma          product 2
WI6703300001     67033                Willy Lamot        product 3

谢谢。

Answer 1

您可以使用ROW_NUMBER：

SELECT *,
      [product_code] = CONCAT(LEFT(suppliers_name,2), suppliers_code,
                              RIGHT('0000' + CAST(rn AS VARCHAR(5)),5)) 
FROM (SELECT *,
             rn = ROW_NUMBER() OVER(PARTITION BY suppliers_code ORDER BY product_name)
      FROM table_name ) AS sub;

如果您使用的是低于SQL Server 2012的版本，请使用+来连接字符串。

的 LiveDemo

Answer 2

在Access中，您可以使用：

Select 
    UCase(Left([suppliers_name], 2)) & [suppliers_code] &
        Format((Select Count(*) From YourTable As T 
            Where T.suppliers_name = YourTable.suppliers_name 
            And T.suppliers_code = YourTable.suppliers_code 
            And T.product_code >= YourTable.product_name), "00000")
        As [product_name] 
From
    YourTable

表中组中的序列号

2 个答案: