Question

我previously请求帮助从C程序（Exe）生成的文本文件中读取数据。

使用@second的解决方案，我解决了问题，但昨天我发现输出文件比我预期的更复杂。

文件输出为：

V|0|0|0|t|0|1|1|4|11|T4|H13||||||||||||  
P|40|0.01|10|1|1|0|40|1|1|1||1|*||0|0|0  
*|A1|A1|A7|A16|F|F|F|F|F|F|||||||||||||  
*|codserv|area|codice|nome|tnom|tmin|tmax|pc|qc|susc|||||||
*|||||kV|kV|kV|MW|MVAR|S||||||||||||  
N|I|1|N01|N01|132|125.4|138.6|0|0||||||||
N|I|1|N02|N02|20|19|21|0|0|||||||||||||
N|I|1|N03|N03|20|19|21|1.013532234|0.49087611||||||||
N|I|1|N04|N04|20|19|21|0.390791617|0.189269056||||||||
N|I|1|N05|N05|20|19|21|0.180634542|0.121387171||||||||
N|I|1|N06|N06|20|19|21|0.709472564|0.343613323||||||||
N|I|1|N07|N07|20|19|21|0.103495727|0.069549543||||||||
N|I|1|N08|N08|20|19|21|0.351712456|0.170342158||||||||
N|I|1|N09|N09|20|19|21|0.097697904|0.06565339||||||||
N|I|1|N10|N10|20|19|21|0.162165157|0.078540184||||||||
N|I|1|N11|N11|20|19|21|0|0||||||||
*|A1|A8|A7|A7|F|F|F|F||F||F 
*|plev|area|codice|estr1|estr2|lung|imax|rsd|xsd|bsd1|bsd2|||
*|||||km|A|Ohm|Ohm||S||S    
L|I|D10203|N02|N03|1.884|360|0.41071|0.207886957|3.19E-08|3.19E-08|||||||||||||
L|I|D10304|N03|N04|1.62|360|0.35316|0.1787563|3.19E-08|3.19E-08|||||||||||||
L|I|D10405|N04|N05|0.532|360|0.11598|0.058702686|3.19E-08|3.19E-08|||||||||||||
L|I|D10506|N05|N06|1.284|360|0.27991|0.14168092|3.19E-08|3.19E-08|||||||||||||
L|I|D10607|N06|N07|1.618|280|0.53879|0.194766124|3.00E-08|3.00E-08|||||||||||||
L|I|D10708|N07|N08|0.532|280|0.17716|0.064039294|3.00E-08|3.00E-08|||||||||||||
L|I|D10809|N08|N09|2|360|0.436|0.220686791|3.19E-08|3.19E-08|||||||||||||
L|I|D10910|N09|N10|2.4|360|0.5232|0.264824149|3.19E-08|3.19E-08||||||||||||
*|A1|A8|A7|A7|F|F|A1|F|F|F|F|F|F||F||F||||||||||||||||||||||||| 
*|codserv|codice|estr1|estr2|vn1|vn2|nod1|varp|varm|np|Pb|rsd|xsd||bsd1||bsd2||||||||||||
*|||||kV|kV||%|%||MVA|%|%||%||%||||| 
%%%%%------%%%%%------%%%% **(read up to here)**
other unnecessary data

算法应该：

跳过前3行
跳过第五行
对于第四行*|codserv|area|codice|nome|tnom|tmin|tmax|pc|qc|susc|||||||，将每个字符串保存在向量空codeserv=[] area=[] codice=[] nome=[] tnom=[] tmin=[] tmax=[] pc=[] qc=[] susc=[]

使用第四个

之后的行中的数据和字符串填充向量

codeserv=[N N N N N N N N N N ....] 
area=[I I I I I I I ....] 
codice=[1 1 1 1 1 1 ...] 
nome=[N01 N02 N03 N04 N05 ] 
tnom=[N01 N02 N03 N04 N05] 
tmin=[132 20 20.....] 
tmax=[125.4 19 19 19 ....] 
pc=[138.6 21 21 21....] 
qc=[0 0 1.013532234 ....] 
susc=[0 0 0.49087611]

对以字母L开头的数据执行相同操作。阅读此行codice|estr1|estr2|lung|imax|rsd|xsd||bsd1||bsd2并使用以L

开头的行填充向量

plev=[L L L L L L L ....] 
area=[I I I I I I I ....]
codice=[D10203 D10304 ...] 
estr1=[N02 N03 N04 N05  ...] 
estr2=[N03 N04 N05...] 
lung=[1.884 1,662 ....] 
imax=[360 360 .....] 
rsd=[number....] 
xsd=[number....] 
bsd1=[number ....] 
bsd2=[number....]

我尝试调整上一个问题中的代码，但考虑到以N和L开头的行不知道有多少我需要知道如何读取第一个字符串和计数数字N和L是。

read
[vp***NNNNNNNNNNNNNNNNNNNNNNNNLLLLLLLLLLLLLLLLLLLLL***] 

length N 

length L 

skip 1 2 3 line

read 4 line, create vector

codeserv=[N N N N N N N N N N ....] 
area=[I I I I I I I ....] 
codice=[1 1 1 1 1 1 ...] 
nome=[N01 N02 N03 N04 N05 ] 
tnom=[N01 N02 N03 N04 N05] 
tmin=[132 20 20.....] 
tmax=[125.4 19 19 19 ....] 
pc=[138.6 21 21 21....] 
qc=[0 0 1.013532234 ....] 
susc=[0 0 0.49087611]

skip length N +1 line

read *|plev|area|codice|estr1|estr2|lung|imax|rsd|xsd|bsd1|bsd2|||

skip length N +3 line

create

plev=[L L L L L L L ....] 
area=[I I I I I I I ....]
codice=[D10203 D10304 ...] 
estr1=[N02 N03 N04 N05  ...] 
estr2=[N03 N04 N05...] 
lung=[1.884 1,662 ....] 
imax=[360 360 .....] 
rsd=[number....] 
xsd=[number....] 
bsd1=[number ....] 
bsd2=[number....]

close the cycle

我希望这是可以理解的。我最大的问题是计算文本中的N和L。

Answer 1

function readtest2()

fid = fopen('test2.txt'); 

skipLines(3)
names1 = getNames;
skipLines(1);
nEntries1 = countPrefix('N');
data1 = textscan(fid,'%s %s %d %s %s %d %d %f %f %f %[| ]', nEntries1, 'delimiter','|');


skipLines(2)
names2 = getNames;
skipLines(1);
nEntries2 = countPrefix('L');
data2 = textscan(fid,'%s %s %s %s %s %f %d %f %f %f %f %[| ]', nEntries2, 'delimiter','|');

fclose(fid);

getData(data1, names1);
getData(data2, names2);



function names = getNames()
  names = fgetl(fid);
  names = textscan(names,'%s','delimiter','|');
end

function getData(data, names)

  for i = 1:size(data,2)-1
    values = ( data{i}(1:end));
    if(iscell(values))
      values = cell2mat(values);
    end

    name = names{1}{i+1};

    % very basic error checking
    if(~strcmp(name, ''))

      %save the value in the calling work space
      assignin('base', name, values)
    end
  end

end


function skipLines(n)
  while(n > 0)
    fgetl(fid);
    n = n - 1;
  end
end

function n = countPrefix(prefix)
  pos = ftell(fid);

  n = 0;
  currLine = fgetl(fid);
  while(currLine(1) == prefix)
    currLine = fgetl(fid);
    n = n + 1;
  end
  fseek(fid, pos, 'bof');
end


end

从MATLAB获取数据的问题

1 个答案: