Question

我有一个布局：

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical">

    <WebView
        android:id="@+id/map_view"
        android:layout_width="match_parent"
        android:layout_height="0dp"
        android:layout_weight="1"/>

    <Button
        android:id="@+id/skip_button"
        android:layout_width="match_parent"
        android:layout_height="@dimen/button_height"
        android:text="@string/skip"/>

</LinearLayout>

当用户在.setVisibility(View.GONE) webview中选择其坐标时，我的代码会隐藏skip_button（通过map_view）。用户还可以重置其坐标，然后按钮必须再次出现。

适用于Android 5，但即使在.setVisibility(View.VISIBLE)之后，Android 4按钮仍保持隐藏状态。我试过了：

mapСontainer.getParent().requestLayout();
mapСontainer.refreshDrawableState();
skipButton.refreshDrawableState();
将webview包装到LinearLayout

但这一切都无济于事。

Answer 1

打败这个。看起来这是一个api16错误，所以我必须解决它......

if (dataOk) {
    skipButton.setVisibility(View.GONE);
    LinearLayout.LayoutParams layoutParams = (LinearLayout.LayoutParams) mapСontainer.getLayoutParams();
    layoutParams.height = 0;
    layoutParams.weight = 1;
    mapСontainer.setLayoutParams(layoutParams);
    mapСontainer.getParent().requestLayout();
} else {
    int visibility = skipButton.getVisibility();
    skipButton.setVisibility(View.VISIBLE);

    if (visibility == View.GONE) {
        int height = mapСontainer.getMeasuredHeight();
        ViewGroup.LayoutParams skipParams = skipButton.getLayoutParams();
        LinearLayout.LayoutParams containerParams = (LinearLayout.LayoutParams) mapСontainer.getLayoutParams();
        containerParams.height = height - skipParams.height;
        containerParams.weight = 0;
        mapСontainer.setLayoutParams(containerParams);
    }
}

邻居GONE / VISIBLE后，Webview（height = 0 / weight = 1）不会重新布局

1 个答案: