Question

我有一个表名Emp_mon_day，其中包括员工目前和缺席详情。

我想要的是

我需要这9名员工，从Emp_mon_day表中合并到以下查询的每个员工的日期和缺席天数信息

QUERY

SELECT e.comp_mkey,
   e.status,
   e.resig_date,
   dt_of_leave,
   e.emp_name,
   e.date_of_joining,
   e.emp_card_no,
   a.pl_days,
   pl_days_opening,
   a.month1,
   a.month2,
   a.month3,
   a.month4,
   a.month5,
   a.month6,
   a.month7,
   a.month8,
   a.month9,
   a.month10,
   a.month11,
   a.month12,       
   a.month1 + a.month2 + a.month3 + a.month4 + a.month5 + a.month6 +   a.month7 + a.month8 + a.month9 + +a.month10 + a.month11 + a.month12 AS pl_sum
  FROM p_leave_allocation AS a
   INNER JOIN
   emp_mst AS e
   ON a.emp_card_no = e.emp_card_no
  WHERE  a.year = 2016
   AND (datediff(MONTH, e.date_of_joining, CONVERT (DATETIME, getdate(), 103)) >= 6
        AND datediff(MONTH, e.date_of_joining, CONVERT (DATETIME, getdate(), 103)) <= 36)
   AND (e.resig_date IS NULL
        OR (e.dt_of_leave IS NOT NULL
            AND e.dt_of_leave >= CONVERT (DATETIME, getdate(), 103)))
   AND e.status IN ('A', 'S')
   AND e.comp_mkey IN (7, 110)
   AND a.Year = 2016;

以上查询为我提供了如下数据

[！[图像数据] [1]] [1]

Emp_mon_day的列详细信息在

之下

[！[在此处输入图像说明] [2]] [2]

Answer 1

您可以尝试以下查询：

SELECT e.comp_mkey, e.status,   e.resig_date,   dt_of_leave,    e.emp_name,
   e.date_of_joining,  e.emp_card_no,   a.pl_days,    pl_days_opening,    a.month1,
   a.month2,   a.month3,   a.month4,   a.month5,   a.month6,   a.month7,   a.month8,
   a.month9,   a.month10,   a.month11,   a.month12,       
   a.month1 + a.month2 + a.month3 + a.month4 + a.month5 + a.month6 +   a.month7 + a.month8 + a.month9 + +a.month10 + a.month11 + a.month12 AS pl_sum,
   m.[DaysAbsent],m.[DaysPresent]
  FROM p_leave_allocation AS a
   INNER JOIN
   emp_mst AS e
   ON a.emp_card_no = e.emp_card_no
   INNER JOIN
   (
   SELECT 
        comp_mkey,emp_mkey,[month],[year], 
        SUM(CASE WHEN data ='AB' THEN 1 ELSE 0 END) AS [DaysAbsent],
        SUM(CASE WHEN data ='P' THEN 1 ELSE 0 END) AS [DaysPresent]
    FROM
        (
        SELECT comp_mkey,emp_mkey,[month],[year],[Day1],[Day2],[Day3],[Day4],[Day5]
        --,...  
        FROM Emp_mon_day
        ) source
        UNPIVOT
        (
        data FOR day IN ([Day1],[Day2],[Day3],[Day4],[Day5]) -- dynamic query can generate all days data
        )up
        GROUP BY comp_mkey, emp_mkey,[month],[year]
   ) AS m
   ON m.comp_mkey=e.Comp_mkey and m.emp_mkey=e.mkey
   --- ABOVE CRITERIA NEEDS TO BE CHECKED
  WHERE  a.year = 2016
   AND (datediff(MONTH, e.date_of_joining, CONVERT (DATETIME, getdate(), 103)) >= 6
        AND datediff(MONTH, e.date_of_joining, CONVERT (DATETIME, getdate(), 103)) <= 36)
   AND (e.resig_date IS NULL
        OR (e.dt_of_leave IS NOT NULL
            AND e.dt_of_leave >= CONVERT (DATETIME, getdate(), 103)))
   AND e.status IN ('A', 'S')
   AND e.comp_mkey IN (7, 110)
   AND a.Year = 2016;

<强>解释

我们在现有查询中添加了另一个INNER JOIN，以获取DaysPresent和DaysAbsent的整理数据

为了进一步优化，我建议您直接将以下WHERE条款应用于source集

WHERE  comp_mkey IN (7, 110) AND Year = 2016;

计算表中存在和不存在的天数

1 个答案: