我们需要一次一个地连续处理来自Azure存储队列的消息。
默认情况下，import SpriteKit
class BackgroundNode: SKNode {
override init() {
super.init()
// create containers for all the Textures and Nodes
var backgroundTextures = [SKTexture]()
var backgroundSpriteNodes = [SKSpriteNode]()
// load the TextureAtlas for the Background
let backgroundAtlas : SKTextureAtlas = SKTextureAtlas(named: "BackgroundImages")
let imagesCount:Int = backgroundAtlas.textureNames.count
// fetch all of the image resources and store them as both textures and spriteNodes
for var i = 1; i <= imagesCount; i++ {
let imageTextureName = "background_\(i)"
let imageTexture = backgroundAtlas.textureNamed(imageTextureName)
let spriteNode = SKSpriteNode(texture: imageTexture)
spriteNode.anchorPoint = CGPointMake(0, 0)
backgroundTextures.append(imageTexture)
backgroundSpriteNodes.append(spriteNode)
}
// for each image figure out what the x value of the location should be
for var i = 0; i < imagesCount; i++ {
var addtionalWidth:CGFloat = 0
// add the x value of all the images before this image to come up with the latest x
for var j = 0; j < i; j++ {
addtionalWidth += backgroundTextures[j].size().width
}
// assign each SKNode a position
backgroundSpriteNodes[i].position = CGPointMake(0 + addtionalWidth, 0)
// add the Node to the scene
self.addChild(backgroundSpriteNodes[i])
}
// keep track of where you are to reset scrolls images
lastNode = backgroundSpriteNodes[imagesCount - 1]
}
required init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
}
var speedOfBackground : CGFloat = 300.0
var previousTime : CFTimeInterval = -1
var lastNode : SKSpriteNode!
func update(currentTime: CFTimeInterval) {
if previousTime != -1 {
var outOfBoundsSprite : SKSpriteNode? = nil
let deltaX = speedOfBackground * CGFloat(currentTime - previousTime)
for sknode in self.children {
if let sprite = sknode as? SKSpriteNode {
sprite.position = CGPointMake(sprite.position.x - deltaX, sprite.position.y)
if (sprite.position.x < -sprite.size.width) {
outOfBoundsSprite = sprite
}
}
}
if (outOfBoundsSprite != nil) {
outOfBoundsSprite?.position.x = lastNode.position.x + lastNode.size.width
lastNode = outOfBoundsSprite!
}
}
previousTime = currentTime
}
}
设置为16
WebJob从队列中取出的16条消息将被并行处理。相反，我们需要WebJob一次一个地连续处理消息。
如何实现这一目标？
我们目前被迫将<div ng-init="foo()">
设置为1，这是不理想的，因为它会在消息队列中读取时引入大量的旋转/停机时间。
澄清：我们不需要先执行先出或保证订单处理，只需一次处理一个。
答案 0 :(得分：2)
JobHostConfiguration config = new JobHostConfiguration();
config.Queues.BatchSize = 1;
config.Queues.MaxDequeueCount = 1;
config.Queues.MaxPollingInterval = TimeSpan.FromSeconds(5);
将BatchSize和MaxDequeueCount设置为1， 将MaxPollingInterval设置为5秒。