我正在尝试实现这个套接字程序,它向所有连接的客户端广播消息。我想要做的是向特定客户广播消息。我试图修改
/ **将给定文本广播给所有客户端。 * / section。
但是,无法摆脱它。任何人都可以为此提出最佳解决方案。
import java.io.*;
import java.net.*;
import java.util.*;
public class ChatServer {
private static final String USAGE = "Usage: java ChatServer";
/** Default port number on which this server to be run. */
private static final int PORT_NUMBER = 8008;
/** List of print writers associated with current clients,
* one for each. */
private List<PrintWriter> clients;
/** Creates a new server. */
public ChatServer() {
clients = new LinkedList<PrintWriter>();
}
/** Starts the server. */
public void start() {
System.out.println("AndyChat server started on port "
+ PORT_NUMBER + "!");
try {
ServerSocket s = new ServerSocket(PORT_NUMBER);
for (;;) {
Socket incoming = s.accept();
new ClientHandler(incoming).start();
}
} catch (Exception e) {
e.printStackTrace();
}
System.out.println("AndyChat server stopped.");
}
/** Adds a new client identified by the given print writer. */
private void addClient(PrintWriter out) {
synchronized(clients) {
clients.add(out);
}
}
/** Adds the client with given print writer. */
private void removeClient(PrintWriter out) {
synchronized(clients) {
clients.remove(out);
}
}
/** Broadcasts the given text to all clients. */
private void broadcast(String msg) {
for (PrintWriter out: clients) {
out.println(msg);
out.flush();
}
}
public static void main(String[] args) {
if (args.length > 0) {
System.out.println(USAGE);
System.exit(-1);
}
new ChatServer().start();
}
/** A thread to serve a client. This class receive messages from a
* client and broadcasts them to all clients including the message
* sender. */
private class ClientHandler extends Thread {
/** Socket to read client messages. */
private Socket incoming;
/** Creates a hander to serve the client on the given socket. */
public ClientHandler(Socket incoming) {
this.incoming = incoming;
}
/** Starts receiving and broadcasting messages. */
public void run() {
PrintWriter out = null;
try {
out = new PrintWriter(
new OutputStreamWriter(incoming.getOutputStream()));
// inform the server of this new client
ChatServer.this.addClient(out);
out.print("G G Connect! ");
out.flush();
BufferedReader in
= new BufferedReader(
new InputStreamReader(incoming.getInputStream()));
for (;;) {
String msg = in.readLine();
if (msg == null) {
break;
} else {
if (msg.trim().equals("BYE"))
break;
System.out.println("Received: " + msg);
// broadcast the receive message
ChatServer.this.broadcast(msg);
}
}
incoming.close();
ChatServer.this.removeClient(out);
} catch (Exception e) {
if (out != null) {
ChatServer.this.removeClient(out);
}
e.printStackTrace();
}
}
}
}
答案 0 :(得分:0)
广播意味着将其发送给每个人。当你说“向一个人播放”时,你的意思是你只是想向一个客户发送消息吗?
如果是这种情况,您需要检索该客户端的PrintWriter
,并通过该对象发送消息:
private void sendMessage(PrintWriter client, String msg) {
client.println(msg);
client.flush();
}
顺便说一句,而不是使用:
for (;;) {
}
您应该使用:
while (true) {
}
更容易识别为无限循环。
哦,不需要在ChatServer.this
中写ChatServer.this.broadcast(msg);
。您只需撰写broadcast(msg):
即可拨打广播留言。