Question

我用Java创建了一个套接字此套接字与服务器连接。

当我启动程序时，服务器会发送一条消息，说明我的套接字与AEOS连接。当我尝试登录服务器发送一些命令时，服务器再次响应：status connected to AEOS version

这不是我期望的消息，通常我的服务器必须发送＆＃34;响应为真＆＃34;。

你能帮帮我吗？

感谢。

import java.io.*;
import java.net.*;

class TCPClient {
    public static void main(String argv[]) throws Exception {
        while(true) {
            String sentence;            
            String modifiedSentence;    

            Socket clientSocket = new Socket("127.0.0.1", 1201);

            BufferedReader inFromUser = new BufferedReader(new InputStreamReader(System.in));
            DataOutputStream outToServer = new DataOutputStream(clientSocket.getOutputStream());        
            BufferedReader inFromServer = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));

            sentence = inFromUser.readLine();
            outToServer.writeBytes(sentence + '\n');
            modifiedSentence = inFromServer.readLine();
            System.out.println("FROM SERVER: " + modifiedSentence);

            clientSocket.close();
        }
    }
}

output socket

Answer 1

为什么不尝试阅读服务器发送的所有内容？另外，每次都需要打开一个新的Socket吗？取决于您的实施。试试这个：

public static void main(String[] args) {

        Socket clientSocket = null;

        try {
            clientSocket = new Socket("127.0.0.1", 1201);

            BufferedReader inFromUser = new BufferedReader(
                    new InputStreamReader(System.in));
            DataOutputStream outToServer = new DataOutputStream(
                    clientSocket.getOutputStream());
            BufferedReader inFromServer = new BufferedReader(
                    new InputStreamReader(clientSocket.getInputStream()));

            String initialMessageFromServer = null;

            while ((initialMessageFromServer = inFromServer
                    .readLine()) != null) {
                System.out.println(initialMessageFromServer);
            }

            while (true) {
                String sentence = inFromUser.readLine();
                outToServer.writeBytes(sentence + '\n');

                StringBuilder modifiedSentence = new StringBuilder();
                String responseFromServer = null;

                while ((responseFromServer = inFromServer.readLine()) != null) {
                    modifiedSentence.append(responseFromServer);
                    modifiedSentence.append('\n');
                }

                System.out
                        .println("FROM SERVER: " + modifiedSentence.toString());
            }
        } catch (Exception e) {
            e.printStackTrace();
        } finally {
            if (clientSocket != null) {
                try {
                    clientSocket.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
    }

Java套接字只发送一条消息

1 个答案: