使用重叠事件计算工作时间(SQL)

时间:2016-03-03 12:23:52

标签: sql sql-server

我在StackOverflow上发现了类似的查询(例如Finding simultaneous events in a database between times),但就我所知,没有任何内容与我所追求的完全匹配,所以认为可以添加为新问题。

我有一个记录作业(或“活动”)的表,其中包含作业的开始/结束时间。我需要计算工作时间(你可以忽略非工作日,休息时间等,因为我已经覆盖了)。复杂性是个人可以同时工作,在不同点重叠(假设是同时工作的同等努力),工作时间需要反映这一点。只需要精确的精确度,而不是秒。

基于其他建议我有这个查询,实现为表值函数。它将查看活动正在运行的每一分钟,以及是否在同一时间内为同一个人运行任何其他活动,并根据该活动进行计算。它有效,但效率很低 - 需要一分钟才能执行。我有什么想法可以更有效地做到这一点吗?

运行SQL 2005.我已经做了很明显的事情,比如顺便在外键上添加索引。

CREATE FUNCTION [dbo].[WorkActivity_WorkTimeCalculations] (@StartDate smalldatetime, @EndDate smalldatetime)
RETURNS @retActivity TABLE
(
ActivityID bigint PRIMARY KEY NOT NULL,
WorkMins decimal NOT NULL
)

/********************************************************************
Summary:        Calculates the WORKING time on each activity running in a given date/time range
Remarks:        Takes into account staff working simultaneously on jobs
            (evenly distributes working time across simultaneous jobs)
Input Params:   @StartDate - the start of the period to calculate
            @EndDate - the end of the period to calculate
Output Params:  
Returns:        Recordset of activities and associated working time (minutes)
********************************************************************/

AS

BEGIN

-- any work activities still running use the overall end date as the activity's end date for the purpose of calculating
-- simulateneous jobs running

-- POPULATE A TEMP TABLE WITH EVERY MINUTE IN THE DATE RANGE
DECLARE @Minutes TABLE (MinuteDateTime smalldatetime NOT NULL)

;WITH cte AS (
SELECT @StartDate AS myDate
UNION ALL
SELECT DATEADD(minute,1,myDate)
FROM cte
WHERE DATEADD(minute,1,myDate) <= @EndDate
)

INSERT INTO @Minutes (MinuteDateTime)
SELECT myDate FROM cte
OPTION (MAXRECURSION 0)

-- POPULATE A TEMP TABLE WITH WORKLOAD PER EMPLOYEE PER MINUTE
DECLARE @JobsRunningByStaff TABLE (StaffID smallint NOT NULL, MinuteDateTime smalldatetime NOT NULL, JobsRunning decimal NOT NULL)

INSERT INTO @JobsRunningByStaff (StaffID, MinuteDateTime, JobsRunning)
SELECT  wka_StaffID, MinuteDateTime, COUNT(DISTINCT wka_ItemID) JobsRunning
FROM    dbo.WorkActivities
        INNER JOIN @Minutes ON (MinuteDateTime BETWEEN wka_StartTime AND DATEADD(minute,-1,ISNULL(wka_EndTime,@EndDate)))
GROUP BY wka_StaffID, MinuteDateTime

-- FINALLY MAKE THE CALCULATIONS FOR EACH ACTIVITY
INSERT INTO @retActivity
SELECT  wka_ActivityID, SUM(1/JobsRunning)WorkMins
FROM    dbo.WorkActivities
        INNER JOIN @JobsRunningByStaff ON (wka_StaffID = StaffID AND MinuteDateTime BETWEEN wka_StartTime AND DATEADD(minute,-1,ISNULL(wka_EndTime,@EndDate)))
GROUP BY wka_ActivityID

RETURN

END

一些示例数据(抱歉格式不佳!)......

WorkActivities表中的源数据:

ACTIVITY ID | START TIME       | END TIME         | STAFF ID
1           | 03/03/2016 10:30 | 03/03/2016 10:50 | 1
2           | 03/03/2016 10:40 | 03/03/2016 11:00 | 1

SELECT * FROM dbo.WorkActivity_WorkTimeCalculations ('03-Mar-2016 10:30','03-Mar-2016 11:30')函数调用所需的结果:

ACTIVITY ID | WORKMINS
1           | 25
2           | 15

因此,结果会考虑到10:40到10:50之间同时发生两个工作,因此在这段时间内计算5分钟的工作时间。

1 个答案:

答案 0 :(得分:0)

正如海报所建议的那样,索引产生了显着的差异 - 使用wka_StartTime创建索引并使用wka_EndTime对其进行排序。

(抱歉,看不出如何将其他人的评论标记为答案!)