Question

我正在测试将PhantomJS服务器与Python的Requests库一起使用的方法。

GET和POST请求按预期工作，我可以让PhantomJS服务器请求我想要的任何页面并将结果放到控制台，但我无法弄清楚如何使用{{1}发回页面内容}。请求对象没有response.write(page.content)，text或可用的content内容。让raw按预期工作的唯一方法是对响应内容进行硬编码。如果我将response.write()添加到keep-alive，则请求函数会挂起。

这是我的true

server.js

Python代码很简单：

var webserver = require('webserver').create();
    page = require('webpage').create();

var service = webserver.listen(8080, function(request, response) {
    if (request.method == 'POST') {
        console.log(request.post);
        var content = '';
        page.open(request.post, function (status) {
            if (status !== 'success') {
                console.log('FAIL to load the address');
                response.statusCode = 200;
                response.write('Page not responding.');
            } else {
                content = page.content;
                response.statusCode = 200;
                response.write(content);
            }
        })
    } else {
        response.statusCode = 200;
        console.log(request.method == 'GET' );
        response.write('No URL provided');
    }
    response.closeGracefully();
});

Answer 1

发送数据后需要关闭连接：response.close();

另外我建议在POST请求中使用变量，因为response.post实际上是一个对象。

var webserver = require('webserver').create();
    page = require('webpage').create();

var service = webserver.listen(8080, function(request, response) {
    if (request.method == 'POST') {
        var url = request.post.url;
        console.log(url);
        var content = '';
        page.open(url, function (status) {
            if (status !== 'success') {
                console.log('FAIL to load the address');
                response.statusCode = 200;
                response.write('Page not responding.');
                response.close();
            } else {
                content = page.content;
                response.statusCode = 200;
                response.write(content);
                response.close();
            }
        })
    } else {
        response.statusCode = 200;
        console.log(request.method == 'GET' );
        response.write('No URL provided');
        respone.close();
    }

});

然后用url变量POST：

import requests
response = requests.post('http://127.0.0.1:8080, data = {'url':'http://python.org'})

使用请求库

1 个答案: