我是acala和akka的新手,所以问题可能有些愚蠢。
我有一个班级:
case class Foo(colUNO: String, colDOS: Long)
我有一个功能:
getById() : Future[Option[Foo]]
我正试图在akka-http路线中使用它
def main(args: Array[String]) {
implicit val actorSystem = ActorSystem("system")
implicit val actorMaterializer = ActorMaterializer()
val route = pathSingleSlash {
get {
complete {
val fut = getById()
}
}
}
Http().bindAndHandle(route,"localhost",8080)
println("server started at 8080")
}
但错误说:
错误:(39,20)类型不匹配;发现: scala.concurrent.Future [选项[com.cassandra.phantom.modeling.MiTabla.User]] 必需:akka.http.scaladsl.marshalling.ToResponseMarshallable getById(ID)
返回Fson的Json需要做些什么?
谢谢!
查看:http://doc.akka.io/docs/akka-stream-and-http-experimental/2.0.3/scala/http/common/json-support.html 并添加以下代码:
import akka.http.scaladsl.marshallers.sprayjson.SprayJsonSupport
import spray.json._
trait JsonSupport extends SprayJsonSupport with DefaultJsonProtocol {
implicit val userFormat = jsonFormat2(Foo)
}
答案 0 :(得分:0)
这将处理您的Future
问题。如果您拥有将Option[com.cassandra.phantom.modeling.MiTabla.User]]
转换为ToResponseMarshallable
val route = pathSingleSlash {
get { ctx =>
ctx.complete(getById())
}
}
答案 1 :(得分:0)
查看:http://doc.akka.io/docs/akka-stream-and-http-experimental/2.0.3/scala/http/common/json-support.html并添加以下代码:
import akka.http.scaladsl.marshallers.sprayjson.SprayJsonSupport
import spray.json._
trait JsonSupport extends SprayJsonSupport with DefaultJsonProtocol {
implicit val userFormat = jsonFormat2(Foo)
}