Question

我有两个单元格数组，

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}];
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}];

对于单元格数组引用， matlab 中是否存在对array2进行排序的智能方法;

该函数应返回array2的索引，顺序与“reference”相同（array2将与引用相同）。

例如

magic_order = function(array2, reference)
....
end

magic_order（array2，reference）将返回

1,4,3,5,2

现在，如果我这样做

array2(1,4,3,5,2)

我会得到与参考

相同的内容

排序功能

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}];
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}];
[a, b] = sort(reference)
isequal(reference, array2(b))
ans = 0

Answer 1

使用intersect：

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}];
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}];

[~, ~, idx] = intersect(reference, array2, 'stable');

返回：

>> isequal(reference, array2(idx))

ans =

     1

使用setOrder='stable'的intersect（我已忽略）的第一个输出，返回reference和array2共有的值，顺序与reference。第三个输出是第一个输出中的array2索引。假设单元格数组相等，这将是array2中reference的索引。

Answer 2

ismember的第二个输出也可能有用。

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}];
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}];
[~, pos] = ismember(reference,array2);

结果：

>> isequal(array2(pos),reference)

ans =

     1

根据另一个单元阵列对单元阵列进行排序

2 个答案: