solve(Amounts) :-
Total = 1505,
Prices = [215, 275, 335, 355, 420, 580],
length(Prices, N),
length(Amounts, N),
Amounts :: 0..Total//min(Prices),
Amounts * Prices #= Total,
labeling(Amounts).
答案 0 :(得分:6)
它没有任何问题。这是来自http://eclipseclp.org/examples/xkcd287.ecl.txt的示例,如果您没有省略该行
:- lib(ic).
加载interval constraint solver,它会在ECLiPSe Prolog中正常工作。
答案 1 :(得分:2)
在SWI-Prolog中也有效:
?- use_module(library(clpfd)).
?- [user].
solve(Amounts) :-
Total = 1505,
Prices = [215,275,335,355,420,580],
length(Prices, N),
length(Amounts, N),
min_list(Prices, MinPrice),
MaxAmount is Total//MinPrice,
Amounts ins 0..MaxAmount,
scalar_product(Prices, Amounts, #=, Total),
label(Amounts).
^D
?- solve(X).
X = [1, 0, 0, 2, 0, 1] ;
X = [7, 0, 0, 0, 0, 0].
但我猜它不是优化搜索问题,
目标函数缺失。
再见