我已经在这里工作了几个小时，但我无法弄清楚这段代码的作用。我知道它是递归的，我认为它计算的是斐波纳契数，但我不确定。有人能指出我正确的方向吗？
转储函数func4的汇编程序代码：
0x0000000000401141 <+0>: push %r12
0x0000000000401143 <+2>: push %rbp
0x0000000000401144 <+3>: push %rbx
0x0000000000401145 <+4>: mov %edi,%ebx
0x0000000000401147 <+6>: test %edi,%edi
0x0000000000401149 <+8>: jle 0x40116f <func4+46>
0x000000000040114b <+10>: mov %esi,%ebp
0x000000000040114d <+12>: mov %esi,%eax
0x000000000040114f <+14>: cmp $0x1,%edi
0x0000000000401152 <+17>: je 0x401174 <func4+51>
0x0000000000401154 <+19>: lea -0x1(%rdi),%edi
0x0000000000401157 <+22>: callq 0x401141 <func4>
0x000000000040115c <+27>: lea (%rax,%rbp,1),%r12d
0x0000000000401160 <+31>: lea -0x2(%rbx),%edi
0x0000000000401163 <+34>: mov %ebp,%esi
0x0000000000401165 <+36>: callq 0x401141 <func4>
0x000000000040116a <+41>: add %r12d,%eax
0x000000000040116d <+44>: jmp 0x401174 <func4+51>
0x000000000040116f <+46>: mov $0x0,%eax
0x0000000000401174 <+51>: pop %rbx
0x0000000000401175 <+52>: pop %rbp
0x0000000000401176 <+53>: pop %r12
0x0000000000401178 <+55>: retq
汇编程序转储结束。
转储函数phase_4的汇编代码：
=> 0x0000000000401179 <+0>: sub $0x18,%rsp
0x000000000040117d <+4>: lea 0x8(%rsp),%rcx
0x0000000000401182 <+9>: lea 0xc(%rsp),%rdx
0x0000000000401187 <+14>: mov $0x402a2d,%esi
0x000000000040118c <+19>: mov $0x0,%eax
0x0000000000401191 <+24>: callq 0x400cb0 <__isoc99_sscanf@plt>
0x0000000000401196 <+29>: cmp $0x2,%eax
0x0000000000401199 <+32>: jne 0x4011a7 <phase_4+46>
0x000000000040119b <+34>: mov 0x8(%rsp),%eax
0x000000000040119f <+38>: sub $0x2,%eax
0x00000000004011a2 <+41>: cmp $0x2,%eax
0x00000000004011a5 <+44>: jbe 0x4011ac <phase_4+51>
0x00000000004011a7 <+46>: callq 0x401701 <explode_bomb>
0x00000000004011ac <+51>: mov 0x8(%rsp),%esi
0x00000000004011b0 <+55>: mov $0x8,%edi
0x00000000004011b5 <+60>: callq 0x401141 <func4>
0x00000000004011ba <+65>: cmp 0xc(%rsp),%eax
0x00000000004011be <+69>: je 0x4011c5 <phase_4+76>
0x00000000004011c0 <+71>: callq 0x401701 <explode_bomb>
0x00000000004011c5 <+76>: add $0x18,%rsp
0x00000000004011c9 <+80>: retq
汇编程序转储结束。
我知道上面的代码测试两个输入和func4使用两个输入。 提前致谢。