我有一个包含2列的简单表:
Col1 | Col2
-----+-----
1 | 3
1 | 4
2 | 3
2 | 4
... many more rows
我想要归还:
Col1 | Col2
-----+-----
1 | 3
2 | 4
我不想要这个:
Col1 | Col2
-----+-----
1 | 3
2 | 3
因为3在Col2中重复,而且
Col1 | Col2
-----+-----
1 | 3
1 | 4
因为1在Col1中重复,而且
Col1 | Col2
-----+----
1 | 3
因为Col2中现在缺少4个。换句话说,我不想要重复,但我也不想省略col2中的任何值(除非它在Col1中出现重复 - 反之亦然)。我如何使用SQL来做我想要的?感谢。
答案 0 :(得分:0)
根据您给定的样本数据进行工作
select col1,
case
when col1 =1 and col2 in (3,4) Then 3
when col1 =2 and col2 in (3,4) Then 4
end as col2
from table1
group by col1
有关详细信息,请转到此处sql fiddle
答案 1 :(得分:0)
我认为您需要这样的查询:
<mvc:View
xmlns="sap.m"
xmlns:html="http://www.w3.org/1999/xhtml"
xmlns:mvc="sap.ui.core.mvc">
<html:ul class="topMenu">
<html:li>
<Button class="linkButton providerReservation" text="{i18n>homePageLinks1}"></Button>
</html:li>
<html:li>
<Button class="linkButton" text="{i18n>homePageLinks2}"></Button>
</html:li>
<html:li>
<Button class="linkButton" text="{i18n>homePageLinks3}"></Button>
</html:li>
<html:li>
<Button class="linkButton" text="{i18n>homePageLinks4}"></Button>
</html:li>
<html:li>
<Button class="linkButton materData" text="{i18n>homePageLinks5}"></Button>
</html:li>
<html:li>
<Button class="linkButton" text="{i18n>homePageLinks6}"></Button>
</html:li>
<html:li>
<Button class="linkButton" text="{i18n>homePageLinks7}"></Button>
</html:li>
</html:ul>
</mvc:View>
SELECT Col1, Col2
FROM
(SELECT dt.*, @rownum1 := @rownum1 + 1 AS rn
FROM
(SELECT Col1
FROM t
GROUP BY Col1) dt,
(SELECT @rownum1 := 0) r) t1
LEFT OUTER JOIN
(SELECT dt.*, @rownum2 := @rownum2 + 1 AS rn
FROM
(SELECT Col2
FROM t
GROUP BY Col2) dt,
(SELECT @rownum2 := 0) r) t2
ON t1.rn = t2.rn
UNION ALL
SELECT Col1, Col2
FROM
(SELECT dt.*, @rownum3 := @rownum3 + 1 AS rn
FROM
(SELECT Col2
FROM t
GROUP BY Col2) dt,
(SELECT @rownum3 := 0) r) t1
LEFT OUTER JOIN
(SELECT dt.*, @rownum4 := @rownum4 + 1 AS rn
FROM
(SELECT Col1
FROM t
GROUP BY Col1) dt,
(SELECT @rownum4 := 0) r) t2
WHERE (t2.Col1 IS NULL);
的不同值。Col1
的不同值。Col2
对FULL OUTER JOIN
行号进行UNION ALL
设置ON
。