为什么声明为final的对象的状态似乎被重置,即使它在匿名函数内被改变了?

时间:2016-03-01 06:09:29

标签: java android

我使用" token",ValueContainer类的实例声明为final,以便保存从JSON请求接收的数据。在匿名函数Response.Listener()中,我设置了令牌的值,它可以工作。

Log.d("myTag", "token value1:" + token.getValue());

此行显示正确的值(非null)。但是,当我再次检查token.getValue()的值时(这次是在匿名函数之外)

Log.d("myTag", "token value2:" + token.getValue());

我得到了token.getValue()= null。我不明白为什么令牌的值似乎被重置为空。我错过了什么吗?

完整代码:

public class MainActivity extends AppCompatActivity {

class ValueContainer<T> {
    private T value;

    public ValueContainer() { }

    public ValueContainer(T value) {
        this.value = value;
    }

    public T getValue() {
        return value;
    }

    public void setValue(T value) {
        this.value = value;
    }
}

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    final ValueContainer<String> token = new ValueContainer<String>();
    String getTokenUrl = "http://www.someurl.com/?somekey=somevalue";

    JsonObjectRequest getTokenRequest = new JsonObjectRequest(
            Request.Method.GET, getTokenUrl, null, new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject response) {
            try {
                token.setValue(response.getString("token"));
                Log.d("myTag", "token value1:" + token.getValue());

                mainTextView.append("Response: JsonObjectRequest successful: get_token: " + token.getValue() + "\n");
            } catch (JSONException e) {
                mainTextView.append("Response: JSONException: getString():" + e);
            }
        }
    }, new Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
            mainTextView.append("Response: JsonObjectRequest failed: " + error + "\n");
        }
    });
    Log.d("myTag", "token value2:" + token.getValue());
}

1 个答案:

答案 0 :(得分:1)

您可以更改&#34;真实内容&#34;一个&#34;最终&#34;对象,但你不能改变它的地址,正如例子所说的那样。

 String stringTest = "test String";

 StringBuffer normalTest = new StringBuffer(stringTest);
 normalTest = normalTest.append(" end");
 normalTest.delete(0, 5);
 System.out.println(normalTest);

 final StringBuffer finalTest = new StringBuffer(stringTest);
// finalTest = finalTest.append(" end"); // can't work;
 finalTest.delete(0, 5);
 System.out.println(finalTest);

您可以按照代码进行测试

//token =  new Token("...")// can't work
token.changeTheToken("...")// work ok