当数组按升序排列时,我尝试使用二进制搜索算法搜索数组。我不知道为什么每次我搜索一个值,它说它不在数组中......这是我的代码。
int main()
{
int found, value;
int array[] = {0,2,2,3,5,9,11,12,12,12,13,17,18,19,19,34}; // array to be searched
cout << "Enter an integer to search for:" << endl;
cin >> value;
found = binarySearch(array, SIZE, value); //function call to perform the binary search
//on array looking for an occurrence of value
if (found == -1)
cout << "The value " << value << " is not in the list" << endl;
else
{
cout << "The value " << value << " is in position number "
<< found + 1 << " of the list" << endl;
}
system("pause");
return 0;
}
//**********BINARY SEARCH**********
int binarySearch(int array[],int numElems,int value) //function heading
{
int first = 0; // First element of list
int last = numElems - 1; // last element of the list
int middle; // variable containing the current
// middle value of the list
while (first <= last)
{
middle = first + (last - first) / 2;
if (array[middle] == value)
return middle; // if value is in the middle, we are done
else if (array[middle] < value)
last = middle - 1; // toss out the second remaining half of
// the array and search the first
else
first = middle + 1; // toss out the first remaining half of
// the array and search the second
}
return -1; // indicates that value is not in the array
}
答案 0 :(得分:2)
二进制搜索的条件被反转。
如果array[middle] < value
那么你想在上半部而不是下半部搜索你的元素。
答案 1 :(得分:0)
交换last = middle - 1
和first = middle + 1
,二分搜索可以正常使用。
让我们搜索7。
2 3 5 6 [7] 8 8 9
0 1 2 3 4 5 6 7
^f
.... ^m
............ ^l
m = (7 + 0) / 2 = 3
索引为3的元素为6。
6 < 7
。然后我们应该将first
更改为mid + 1
。
如果中间值小于搜索值,那么我们应该更改first
,以便搜索值仍然在[first; last]
区间