Question

以下是我要做的事情：

在库中建立一系列影片剪辑
随机化数组中的顺序
在输入框架上，显示随机数组中的第一个影片剪辑
单击“下一步”按钮时，将加载现有的带卸载的剪辑和数组顺序中的下一个移动剪辑
显示阵列中的最后一个影片剪辑并单击“下一步”按钮后，将加载阵列中的第一个影片剪辑。
如果用户一直点击“下一步”按钮，这将反复重复。

这是我到目前为止建立随机数组的代码：

var animalArray:Array = ["animal1","animal2","animal3","animal4","animal5","animal6","animal7",]; 
var animalIndex:int = -1; 

function getNextanimal():String {
    if(animalIndex == -1) animalIndex = Math.round(Math.random() * (animalArray.length - 1)); 

    animalIndex++; //increment it
    if(animalIndex >= animalArray.length) animalIndex = 0; 

    return animalArray[animalIndex];
}

这是我按钮的代码：

button.addEventListener(MouseEvent.CLICK, clickCard);
function clickCard(event: MouseEvent): void {

    var animalCard: String = getNextanimal();
    addChild(animalCard);

}

单击按钮时我只会收到错误。有什么建议吗？

Answer 1

以下是一种可以执行此操作的方法：

//create your array (nothing changed here, though you could do this in a loop if all items follow a numerical pattern like it appears they do)
var animalArray:Array = ["animal1", "animal2", "animal3", "animal4", "animal5", "animal6", "animal7", ];

//create a function that randomizes the array:
function randomSort(a:*, b:*):int {
    return ( Math.random() > .5 ) ? 1 : -1;
}

//sort the array using the function above   
animalArray.sort(randomSort);

//copy the array so you can reset it after getting to the end of a cycle
var origArray:Array = animalArray.concat();

//get the next animal
function getNextAnimal():String {
    //if the array is now empty, copy the original array (you could also re-randomize here if desired)
    if (!animalArray.length) animalArray = origArray.concat();

    //pop takes the last item of the array (and removes it from the array)
    return(animalArray.pop());
}

现在，您遇到的错误可能是尝试使用addChild并将字符串作为参数（它期望显示对象）的结果。

如果这些动物实际上是实例名称，只需使用getChildByName：

addChild(getChildByName(getNextAnimal));

如果它们是从库中导出的链接ID，那么使用它们是实际的类名而不是数组中的字符串，然后实例化它们：

var animalArray:Array = [Animal1, Animal2, Animal3, Animal4];

//then later:
function getNextAnimal():Class  ...

//then later:
var cls:Class = getNextAnimal();
addChild(new cls());

所以，你的下一次点击应该是这样的：

button.addEventListener(MouseEvent.CLICK, clickCard);    
var curItem:DisplayObject; //you need a var to keep track of the last item added

function clickCard(event: MouseEvent): void {
    //if there is a current item and it has a parent, remove it
    if(curItem && curItem.parent) removeChild(curItem);
    var cls:Class = getNextAnimal();
    curItem = new cls();
    addChild(curItem);
}

修改

知道你使用的是Linkage ID，我就是这样写的：

//a vector is just like an array, except all members have to be of the specified type
var animalArray:Vector.<Class> = new <Class>[animal1, animal2, animal3];

function randomSort(a:*, b:*):int {
    return ( Math.random() > .5 ) ? 1 : -1;
}

animalArray.sort(randomSort);
var origArray:Vector.<Class> = animalArray.concat();

function getNextAnimal():Class {
    if (!animalArray.length) animalArray = origArray.concat();
    return(animalArray.pop());
}

button.addEventListener(MouseEvent.CLICK, clickCard);    
var curItem:DisplayObject; //a var to keep track of the last item added

function clickCard(event: MouseEvent): void {
    //if there is a current item and it has a parent, remove it
    if(curItem && curItem.parent) removeChild(curItem);
    var cls:Class = getNextAnimal();
    curItem = new cls();
    addChild(curItem);
}

按顺序显示数组中的动画片段

1 个答案:

修改