我在PHP脚本的下一行收到此错误,该脚本负责执行mysqli_query。我不确定它为什么会出现在那里:
syntax error, unexpected T_VARIABLE, expecting ']'
<?php
$response = array("error" => FALSE);
if (isset($_POST['city']) && isset($_POST['offset']) != '') {
$city= $_POST['city'];
$offset = $_POST['offset];
$conn=mysqli_connect("****.com", "***", "***","****");
$get_images= mysqli_query($conn,"SELECT user_id, image, longitude, latitude, city, geo_name_id, description, score, Categories FROM images WHERE geo_name_id = '$city' LIMIT 10 OFFSET '$offset'");
$myArray = array();
$returnArray = array();
while($row = $get_images->fetch_array())
{
$myArray["user_id"] = $row["user_id"];
$myArray["image"] = $row["image"];
$myArray["longitude"] = $row["longitude"];
$myArray["latitude"] = $row["latitude"];
$myArray["city"] = $row["city"];
$myArray["geo_name_id"] = $row["geo_name_id"];
$myArray["description"] = $row["description"];
$myArray["score"] = $row["score"];
$myArray["Categories"] = $row["Categories"];
$returnArray[] = $myArray;
}
echo json_encode($returnArray);
}
?>
我真的没有看到]
在这里......
答案 0 :(得分:2)
您错过了以下的详细报价:
$offset = $_POST['offset'];
应该是:javamail api
而不是。