Question

我正在使用TapGestureRecognizer创建一个具有可变数量视图的应用。按下视图时，我目前正在执行此操作

func addView(headline: String) {
    // ...
    let theHeadline = headline
    let tapRecognizer = UITapGestureRecognizer(target: self, action: Selector("handleTap:"))
    // ....
}

但在我的功能＆＃34; handleTap＆＃34;中，我想给它一个额外的参数（而不仅仅是发送者），如此

func handleTap(sender: UITapGestureRecognizer? = nil, headline: String) {
}

如何将特定标题（每个视图都是唯一的）作为handleTap函数的参数发送？

Answer 1

不是创建通用的UITapGestureRecognizer，而是将其子类化并为标题添加属性：

class MyTapGestureRecognizer: UITapGestureRecognizer {
    var headline: String?
}

然后使用它：

override func viewDidLoad() {
    super.viewDidLoad()

    let gestureRecognizer = MyTapGestureRecognizer(target: self, action: "tapped:")
    gestureRecognizer.headline = "Kilroy was here."
    view1.addGestureRecognizer(gestureRecognizer)
}

func tapped(gestureRecognizer: MyTapGestureRecognizer) {
    if let headline = gestureRecognizer.headline {
        // Do fun stuff.
    }
}

我试过这个。它运作得很好。

通过UITapGestureRecognizer选择器向函数发送参数参数

1 个答案: