Question

我有一个包含st_id列的表格。

每列都有amount.eg jan_1,feb_1有两行。一个用于jan_2,feb_2数据，另一个用于SELECT st_id,SUM(jan_1+feb_1) as amt1,SUM(jan_2+feb_2) as amt2 FROM fee_amount WHERE `st_id` IN (5,7,8);数量。

我想要每个id的一行。现在我只得到了所有金额的一行。

查询：

autoHighlight="true"

Answer 1

您需要GROUP BY st_id。因此，您将获得每个st_id的每一行。

SELECT 
 st_id,
 SUM(jan_1+feb_1) as amt1,
 SUM(jan_2+feb_2) as amt2 
FROM fee_amount WHERE `st_id` IN (5,7,8)
GROUP BY `st_id`;

注意：没有Group By的聚合函数会将结果集折叠为一行。

See Demo

Answer 2

在您的查询中，最后只添加GROUP BY子句（ GROUP BY st_id ）。

SELECT 
 st_id,
 SUM(jan_1+feb_1) as amt1,
 SUM(jan_2+feb_2) as amt2 
 FROM fee_amount 
 WHERE `st_id` IN (5,7,8)
 GROUP BY `st_id`;

Answer 3

合理的方法是将（jan_1 + jan2）求和为Jan，同时对feb数据进行相同的处理。

以下是查询：

SELECT 
    st_id,
    SUM(jan_1 + jan_2) AS jan,
    SUM(feb_1 + feb_2) AS feb
FROM
    fee_amount 
WHERE 
    `st_id` IN (5,7,8)
GROUP BY
    st_id;

Answer 4

SELECT st_id,
       Sum(jan_1 + feb_1) AS amt1,
       Sum(jan_2 + feb_2) AS amt2
FROM   fee_amount
WHERE ` st_id ` IN ( 5, 7, 8 )
GROUP  BY ` st_id ` ;

如何获得个人身份证的所有总和？

4 个答案: