Question

我必须制作代码，使得Finch机器人在通过水龙头激活后跟踪物体，并且当它被轻敲两次时程序退出。我无法理解如何做到这一点。现在，我试图让它在机器人被激活之后（它将在while（x == 1）代码之后），每次点击机器人时它会向'tappedCount'添加1。

然而，由于程序将始终在其他'while'循环内工作（在if语句中检查对象的位置，因为Finch的性质，其中一个将始终激活。这意味着：

if(myf.isTapped())
    {
        tappedCount++;
    }
if(tappedCount==2)
    {
        System.out.println("Exiting Finch");
        System.exit(0);
        myf.quit();
    }

代码永远不会有机会运行。

有没有人建议如何让它运行？或者当机器人被轻敲两次时退出程序的另一种方法会很棒。谢谢。

import edu.cmu.ri.createlab.terk.robot.finch.Finch;
public class FinchCode {

static long instant1;
static long instant2;
static long instant3;
static long instant4;
static long duration;
static long duration1;
static int x = 0;

static int Buzz = 300;
static int BuzzDuration = 1200;

static int R = 250;
static int G = 250;

static int velocityLeft = 150;
static int velocityRight = 150;

static int turnLeft = -100;
static int turnRight = -100;

static int time = 0;
static int tappedCount = 0;
static int millis;
public static void main(String[] args) throws InterruptedException{


    Finch myf = new Finch();    

    while(!myf.isBeakDown())
    {
        if(myf.isTapped()&& x==0)
        {
            if(myf.isObstacleLeftSide()&&myf.isObstacleRightSide())
            {
                x = 1;
                myf.setLED(R,0,0);
                myf.stopWheels();       
            }
        }
        while(x==1)
        {
            if(myf.isTapped())
            {
                tappedCount++;
            }
            if(tappedCount==2)
            {
                System.out.println("Exiting Finch");
                System.exit(0);
                myf.quit();
            }
            if(!myf.isObstacleLeftSide()&&!myf.isObstacleRightSide())
            {
                while(!myf.isObstacleLeftSide()&&!myf.isObstacleRightSide())
                {   
                    myf.setLED(0,G,0);
                    myf.setWheelVelocities(velocityLeft, velocityRight);
                }
                System.out.println("Forward");
            }
            if(!myf.isObstacleLeftSide()&&myf.isObstacleRightSide())
            {
                while(!myf.isObstacleLeftSide()&&myf.isObstacleRightSide())
                {
                    myf.setLED(0,G,0);
                    myf.setWheelVelocities(velocityLeft, turnRight);
                }
                System.out.println("Right");
            }
            if(myf.isObstacleLeftSide()&&!myf.isObstacleRightSide())
            {
                while(myf.isObstacleLeftSide()&&!myf.isObstacleRightSide())
                {
                    myf.setLED(0,G,0);
                    myf.setWheelVelocities(turnLeft, velocityRight);
                }
                System.out.println("Left");
            }
            if(myf.isObstacleLeftSide()&&myf.isObstacleRightSide())
            {
                while(myf.isObstacleLeftSide()&&myf.isObstacleRightSide())
                {
                    myf.setLED(R,0,0);
                    myf.stopWheels();                       
                }
                System.out.println("Stop");
            }
        }
    }
}

Answer 1

    boolean move = false;
    if(myf.isTapped())
    {
           move = true;
    }
     while(move)
        {
           //Code keeping the finch moving
           //check at the end of loop if the tapp has occured yet
           //if so reset to false, and the while loop will exit
           if(myf.isTapped())
           {
           move = false;
           }
        }
     //Exit program and print your stuff          
            System.out.println("Exiting Finch");
            System.exit(0);
            myf.quit();

如何在执行while循环时测试if语句

1 个答案: