Question

print ("Selection of the mode\n Easy \n Moderate \n tough")
selection = int(input("Please enter the right Choice!! > "))

while selection != '':
    if selection == 1:
        print("\ngoodluck")
    elif selection == 2:
        print('\nyou are brave')
    elif selection == 3:
        print ('\nyou must be kidding')
    selection = int(input("Please enter the right Choice!!! > "))

我正在创建一个小程序，对python是新的，所以有一些理解问题，需要知道我的错误，当用户输入正确的选择，如1或2或3时，它应该进入循环并运行如果声明。一旦完成，它应该退出。但显然这种方法并不完美。

print ("Selection of the mode\n Easy \n Moderate \n tough")
selection = input("Please enter the right Choice!! > ")

while selection != '':
    if selection == '1':
        print("\ngoodluck")
        break
    elif selection == '2':
        print('\nyou are brave')
        break
    elif selection == '3':
        print ('\nyou must be kidding')
        break
    selection = input("Please enter the right Choice!!! > ")

我现在正在执行此操作，但会查看所有if语句，但我只想在第一个选择正确的if语句后退出。

Answer 1

试试这个

print ("Selection of the mode\n Easy \n Moderate \n tough")
selection = int(input("Please enter the right Choice!! > "))

while selection != '':
    if selection == 1:
        print("\ngoodluck")
        break
    elif selection == 2:
        print('\nyou are brave')
        break
    elif selection == 3:
        print ('\nyou must be kidding')
        break
    selection = input("Please enter the right Choice!!! > ")

此外，多次不需要input()。

print ("Selection of the mode\n Easy \n Moderate \n tough")
while True:
    selection = int(input("Please enter the right Choice!!! > "))
    if selection == 1:
        print("\ngoodluck")
        break
    elif selection == 2:
        print('\nyou are brave')
        break
    elif selection == 3:
        print ('\nyou must be kidding')
        break

while循环使用python中的if语句

1 个答案: