好的我正在制作一个简单的基于文本的游戏，我不确定为什么会创建无限循环。它不是真的无限但我不确定为什么if语句不会在每个循环中被评估。这是整个计划。我需要修复的if语句位于代码末尾的roomEight方法中。
//********************************
// A simple game that moves the
// player though the map
//********************************
import java.util.*;
import java.text.*;
public class mazegame
{
private static Scanner scan = new Scanner (System.in); // starts scanner for the program
public static Scanner scanS;
// ScanS is a scanner for strings.
// To call this variable type mazegame.scanP;
public static int lifeCount = 15;
public static int damage = 1;
// imp stats
public static int impAmount = 0;
public static int impDamage = 1;
public static int impLife = 1;
// Low level monster stats
// m followed by a number stands for monster then the level of monster
public static int m1health = 5;
public static int m1damage = 2;
// High level monster
public static int m2health = 10;
public static int m2damage = 2;
// Boss stats
public static int bosshealth = 30;
public static int bossdamage = 10;
// Placement of player
public static int placement = 3;
public static String movement;
public static int scanVal; // holder a scanner value generic.
public static void main(String[] args)
{
System.out.println("You wake up on a cold hard floor");
time();
System.out.println("you are unsure how you got there.");
time();
System.out.println("There is an opening a head");
time();
System.out.println("you walk forward into the opening the ground begins to tremble");
time();
System.out.println("the wall behind you closes you are trapped.");
time();
time();
clear(); // clears screen for user.
roomThree();
}
public static void timeHalfSec()
{
try
{
Thread.sleep(500); //1000 milliseconds is one second.
}catch(InterruptedException ex)
{
Thread.currentThread().interrupt();
}
}
public static void time()
{
try
{
Thread.sleep(1500); //1000 milliseconds is one second.
}catch(InterruptedException ex)
{
Thread.currentThread().interrupt();
}
}
public static void clear()
{
final String ANSI_CLS = "\u001b[2J";
final String ANSI_HOME = "\u001b[H";
System.out.print(ANSI_CLS + ANSI_HOME);
System.out.flush();
}
public static void position(int placement)
{
switch( placement )
{
//********************************
// For each room create a method and
// call it in this switch statement.
//********************************
case 1:
break;
case 2:
break;
case 3:
break;
case 4:
break;
case 5:
break;
case 6:
break;
case 7:
break;
case 8: roomEight();
break;
case 9:
break;
case 10:
break;
case 11:
break;
case 12:
break;
case 13:
break;
case 14:
break;
case 15:
break;
case 16:
break;
case 17:
break;
case 18:
break;
case 19:
break;
case 20:
break;
case 21:
break;
case 22:
break;
case 23:
break;
case 24:
break;
case 25:
break;
}
}
public static void askMove()
{
System.out.println("You can walk forward, left , or right. Beware the imps.");
System.out.println("Enter L for left, R for right, and F for forward.");
time();
System.out.print("Move:");
movement = scan.nextLine();
}
public static void roomThree()
{
askMove();
//--------------------------------
// This switch stament is only for this room
//--------------------------------
switch ( movement )
{
case "l":
case "L":
placement = 2;
System.out.println("Changing rooms Please wait");
time();
clear();
break;
case "r":
case "R":
placement = 4;
System.out.println("Changing rooms Please wait");
time();
clear();
break;
case "f":
case "F":
placement = 8;
System.out.println("Changing rooms Please wait");
time();
clear();
break;
}
// The switch statement changes position and position calls the next room method.
position(placement);
}
public static void roomEight()
{
System.out.print ("You have just entered a new room.");
System.out.print ("There is an imp ahead would you like to see its stats? 1 for yes and 0 ");
impAmount = 1;
scanVal = scan.nextInt();
if(scanVal == 1 )
{
impStats();
}
System.out.println("Would you like to hit the imp? 1 for yes and 0 for no.");
scanVal = scan.nextInt();
while (impAmount != 0)
{
if (scanVal == 1)
{
impAmount = 0;
damage++;
lifeCount = 15;
System.out.println("You killed an imp! You found brass knuckles your damage increased by one. Here are your stats");
playerStats();
}else{
lifeCount--;
System.out.println("The imp hit you. You took one damage");
playerStats();
timeHalfSec();
dead();
}
}
}
public static void playerStats()
{
System.out.println("*----------------*");
System.out.println("Your Hearts: " + lifeCount);
System.out.println("Your Damage: " + damage);
System.out.println("*----------------*");
}
public static void impStats()
{
System.out.println ("*----------------*");
System.out.println("Amount of Imps: " + impAmount);
System.out.println("Imp Health: 1");
System.out.println("impDamage: 1");
System.out.println("*----------------*");
}
public static void dead()
{
if(lifeCount < 1)
{
System.exit(0);
}
}
}
//********************************************************************************************************************************
// Places to look for code and things to look up.
// Lookup: .equalsIgnoreCase, global scanner.
// Places to look for code:
// http://stackoverflow.com/questions/23586732/how-to-make-a-one-static-scanner-global-variable-without-closing-scan-constantly
// https://www.youtube.com/watch?v=zijvKOjnmwY
// http://stackoverflow.com/questions/16706716/using-two-values-for-one-switch-case-statement
// http://www.csci.csusb.edu/dick/samples/java.classes.html#System
// http://stackoverflow.com/questions/22452930/terminating-a-java-program
//
//
//
//********************************************************************************************************************************
答案 0 :(得分：0)
您可能希望将以下两行移动到循环中：
System.out.println("Would you like to hit the imp? 1 for yes and 0 for no.");
scanVal = scan.nextInt();
答案 1 :(得分：0)
正如我所看到的，你扫描用户输入的nextInt，你用它做的东西，然后你重新扫描nextInt。问题是当你使用扫描仪并要求一个int时，扫描仪中仍然有新行字符（'\ n'）。因此，当您第二次询问int时，这将返回新的行char。我对这一切的理解不是重点，但你要做的就是解决方案之一：
使用nextLine代替nextInt并将字符串值解析为Int。这将清除缓冲区，您将能够验证用户是否输入了有效的Int。你这样做：
String scanVal = scan.nextLine();
//You can add some try catch in order to validate the int being parsed
int choice = Integer.parseInt(scanVal);
或者您可以在scan.nextLine()
scan.nextInt()扫描您的整数后清除缓冲区
希望这有帮助！