Question

我正在创建一个只是Shell游戏的C ++程序。我有一个问题，如果用户的猜测是不正确的，他们再次猜测，它不再检查猜测。相反，它只是返回主菜单。我猜这一定是范围问题，但我不太确定。任何帮助将不胜感激。

 #include <iostream>
 #include <array>

using namespace std;

void displayMenu();
void displayGameMenu ();


int main() {
int userChoice;
int n;
do {
    int incorrectGuess;
    displayMenu();
    cin >> userChoice;
    if (userChoice == 1) {
        displayGameMenu();
        cin >> n;
        if (n < 3) {
            cout << "The minimum number of cups is 3. Please enter the amount of cups you'd like to play with: " << endl;
            cin >> n;
        }
        else {
            bool cups[n];
            cout << "The game is ready, and the ball is under one of the " << n << " cups. Guess which cup the ball is in: \n";
            for (int i = 0; i < n; i++) {
                cout << "Cup " << i + 1 << "\n";
            }
            cout << "Enter -1 to leave the game. ";
            int ballLocation = rand()%(n-3) + 3;
            cups[ballLocation] = true;
            int userGuess;
            cin >> userGuess;
            if (userGuess == ballLocation) {
                cout << "Congrats! You win! What would you like to do now?\n";
                return 0;
            }
            else if (userGuess != ballLocation) {

                cout << "Nope! Not it! Try again: \n";
                for (int i = 0; i < n; i++) {
                    cout << "Cup " << i + 1 << "\n";
                }
                cout << "Enter -1 to leave the game. ";
                cin >> userGuess;
                ballLocation = rand()%(n-3) + 3;
                incorrectGuess++;
            }
            else if (userGuess > n) {
                cout << "Invalid guess! Try again: ";
                for (int i = 0; i < n; i++) {
                    cout << "Cup " << i + 1 << "\n";
                }
                cout << "Enter -1 to leave the game. ";
                cin >> userGuess;
            }
            else if (incorrectGuess == 4) {
                cout << "You're out of guesses! Nice try! \n";
                return 0;
            }
            else if ( userGuess == -1) {
                return 0;
            }
        }
    }
}
    while (userChoice != 2);

}
void displayMenu() {
cout << "Welcome to the Shell Game! Please choose one of the menu options   below.\n";
cout << "1. Play the Game!\n";
cout << "2. Quit.\n";
cout << "Enter choice here: " << endl;
}

void displayGameMenu() {
cout << "Thank you for deciding to play the Shell Game. How many cups (3 is the minimum) would you like to play with? " << endl;
}

Answer 1

您的while循环将执行范围括号中的所有内容：

do
{
   // EVERYthing in here is performed within the while loop
} while ();

现在看看你的范围：

do
{
    ...
    displayMenu();
    ...
} while (userChoice != 2);

你看到了问题吗？您告诉您的while循环在循环的每次迭代中显示菜单！您可能希望将displayMenu()放在do while

之前

C ++程序未正确执行，可能是范围问题

1 个答案: