Question

我不确定如何使用spark-submit启动Java应用。

当我运行以下命令时：

spark@mcava-master:/home/miren/NetBeansProjects$ /opt/spark/bin/spark-submit --class /home/miren/NetBeansProjects/SparkExample/src/main/java/com/mycompany/sparkexample/CountWords.java --master spark://192.168.1.105:7077 /home/miren/NetBeansProjects/SparkExample/target/SparkExample-1.0-SNAPSHOT.jar spark://192.168.1.105:7077

我得到一个例外：

java.lang.ClassNotFoundException: /home/miren/NetBeansProjects/SparkExample/src/main/java/com/mycompany/sparkexample/CountWords.java
    at java.lang.Class.forName0(Native Method)
    at java.lang.Class.forName(Class.java:348)
    at org.apache.spark.util.Utils$.classForName(Utils.scala:174)
    at org.apache.spark.deploy.SparkSubmit$.org$apache$spark$deploy$SparkSubmit$$runMain(SparkSubmit.scala:689)
    at org.apache.spark.deploy.SparkSubmit$.doRunMain$1(SparkSubmit.scala:181)
    at org.apache.spark.deploy.SparkSubmit$.submit(SparkSubmit.scala:206)
    at org.apache.spark.deploy.SparkSubmit$.main(SparkSubmit.scala:121)
    at org.apache.spark.deploy.SparkSubmit.main(SparkSubmit.scala)

如何指明类路径？

Answer 1

您需要通过以下方式致电spark-submit：

spark-submit --class com.mycompany.sparkexample.CountWords 
             --master spark://192.168.1.105:7077 
             /home/miren/NetBeansProjects/SparkExample/target/SparkExample-1.0-SNAPSHOT.jar 
             {your-app-arguments-here}

--class参数获取包含主方法的对象的fully qualified name。

documentation包含有关正确使用spark-submit的更多信息。

使用spark-submit运行Spark应用程序时出现ClassNotFoundException

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