Question

我一直在尝试使用MUD-PI编写一个多用户地牢，并且我坚持制作一个战斗命令我想让它像杀怪[怪物]一个例子就像杀死巨魔。

这是我的命令代码

elif command == "kill":
            mn = params.lower()
            rm = rooms[players[id]["room"]]
            if rm["enemy"] == 'yes':

                if mn in rm["monsterName"]:
                    monster = mn
                    if monster.hp >= 0:
                        mud.send_message(id,"You attack %s for %d damage" % (rm["monsterName"], players[id]["ATK"]))
                        monster.hp -= players[id]["ATK"]
                    else:
                        monster.death()
                else:
                    mud.send_message(id, "you dont see a %s" % mn)
            else:
                mud.send_message(id, "you dont see an enemy")

这是我的房间代码。

#Rooms

import sys, random, os

#import monsters
from Monsters import *
# structure defining the rooms in the game. Try adding more rooms to the game!
rooms = {
    "Tavern": {
        "description": "You're in a cozy tavern warmed by an open fire.",
        "exits": { "outside": "Outside" },
    },
    "Outside": {
        "description": "You're standing outside a tavern. there is a troll.",
        "exits": { "inside": "Tavern" },
        "enemy": "yes",
        "monsterName": {"troll": troll },
    }
}

我的怪物代码。

#monsters

import sys,random,os,time



#Troll
class Troll():
    def __init__(self):
        self.name = "Troll"
        self.ATK = 2
        self.hp = 10
        self.max_hp = 10

    def death(self):
        mud.send_message(id,"you killed the troll")
        self.hp = self.max_hp


troll = Troll()

当我尝试kill命令时，我收到此错误。

    if monster.hp >= 0:
AttributeError: 'unicode' object has no attribute 'hp'

我想知道是否有更好的方法来做到这一点，如果是这样，如果不能如何解决我的问题。

Answer 1

您确定要行吗

monster = mn

将怪物的名称分配给monster而不是其对象。我认为它需要看起来更像

monster = rm["monsterName"][mn]

Python多用户地牢（MUD）命令

1 个答案: