我是mongo，scala和salat的新手
我有json集合
{[
{"firstName":"John", "lastName":"Doe", department="IT", skills="java"},
{"firstName":"Anna", "lastName":"Smith", department="accounts, skills="tally"},
{"firstName":"Peter", "lastName":"Jones", department="It" skills="java" }
]}
我将案例类定义如下
case class Employee(firstName:String,lastName:String,department:String,skills:String)
使用salatdao如下
object EmployeeDao extends SalatDAO[Employees, ObjectId](collection =employee_collection)
和让员工这样的方法
def getEmployees(IT : String):List[Employees]={
val listOfEmployees:List[Employees] = OrderDAO3.find(MongoDBObject({"department"->IT})).toList
return listOfEmployees
}
得到结果......
{[ {＆＃34; firstName＆＃34;：＆＃34; John＆＃34;，＆＃34; lastName＆＃34;：＆＃34; Doe＆＃34;，department =＆＃34; IT＆＃34;，skills = ＆＃34;的java＆＃34;}， {＆＃34; firstName＆＃34;：＆＃34; Peter＆＃34;，＆＃34; lastName＆＃34;：＆＃34; Jones＆＃34;，department =＆＃34; IT＆＃34;技能=＆＃34;的java＆＃34; } ]}
到目前为止一切顺利......现在我想要GROUP BY ALL DEPARTMENTS并想要这样的结果
{"IT":[
{"firstName":"John", "lastName":"Doe"},
{"firstName":"Anna", "lastName":"Smith"},
{"firstName":"Peter", "lastName":"Jones"}
]
{"accounts":[
{"firstName":"Johnac", "lastName":"Doeac"},
{"firstName":"Annaac", "lastName":"Smithac"},
{"firstName":"Peterac", "lastName":"Jonesac"}
]}
}
所以请告诉我如何编写MongoDBObject来获得此结果，并建议我使用相应的案例类来保存该集合。