Question

我被要求报告提供商当月收取的费用。当前的标准是一个代码意味着一个费用。我现在遇到的问题是，他们为其中一个提供程序添加了一个例外。其中，如果以F开头或以G结尾的代码在服务的同一天中有1位患者使用4或5个代码，则它们仅计为3个费用。

For example (Pv2 is the one with the special case)
Prov       Patient       ServiceDate       Code
Pv1          Pt1           1/1/2019        99001
Pv1          Pt2           1/4/2019        99004
Pv1          Pt2           1/2/2019        F0001
Pv2          Pt1           1/1/2019        F0001
PV2          Pt1           1/1/2019        1000G
PV2          Pt1           1/1/2019        F0012
PV2          Pt1           1/1/2019        1003G
PV2          Pt1           1/1/2019        F1100
PV2          Pt2           1/4/2019        99001

报告应如下所示

Prov         ChargeCount
Pv1            3
Pv2            4

这是我当前的代码：

Select Prov, Count(Code)
From Table
Group by Prov

所以我的输出

Prov         ChargeCount
Pv1            3
Pv2            6

Answer 1

这是可以满足您需要的功能代码，是我要采用的第一种方法。基本上，您将例外情况和标准案例分别进行总计，然后应用例外情况调整并将这两个值加在一起。

With DataGather as (
    SELECT
        Prov,
        SUM(CASE 
                WHEN Code Like 'F%' Or Code Like '%G' 
                    Then 1
                Else 0
            END
        ) as FGCodes,
        SUM(CASE
                WHEN WHEN Code Like 'F%' Or Code Like '%G' 
                    Then 0
                Else 1
            END
        ) as Codes
    FROM Table
    GROUP BY Prov
    )
SELECT Prov,
    Codes + 
        CASE
            WHEN FGCodes > 3
                THEN 3
            ELSE FGCodes
        END as ChargeCount
FROM DataGather

编辑：

在附加条件下，最后一个CASE语句可以重写为：

    CASE 
        WHEN FGCodes <= 3
            THEN FGCodes
        WHEN FGCodes <= 5
            THEN 3
        ELSE 5
    END as ChargeCount

Answer 2

您可以尝试使用以下CTE代码-

WITH CTE AS
(
    SELECT Prov,Patient, 3 CNT
    FROM your_table
    WHERE YEAR(ServiceDate)  = 2019
    AND MONTH(ServiceDate) = 1
    AND (
        LEFT(Code,1) = 'F' OR RIGHT(Code,1)  = 'G'
    )
    GROUP BY Prov,Patient
    HAVING COUNT(Code) IN (4,5)

    UNION ALL

    SELECT Prov,Patient, COUNT(Code) 
    FROM your_table
    WHERE YEAR(ServiceDate)  = 2019
    AND MONTH(ServiceDate) = 1
    AND (
        LEFT(Code,1) = 'F' OR RIGHT(Code,1)  = 'G'
    )
    GROUP BY Prov,Patient
    HAVING COUNT(Code) NOT IN (4,5)

    UNION ALL

    SELECT Prov,Patient, COUNT(Code) 
    FROM your_table
    WHERE YEAR(ServiceDate)  = 2019
    AND MONTH(ServiceDate) = 1
    AND LEFT(Code,1) <> 'F' 
    AND RIGHT(Code,1)  <> 'G'
    GROUP BY Prov,Patient
)

SELECT Prov, SUM(CNT) ChargeCount
FROM CTE
GROUP BY Prov

输出为-

Prov    ChargeCount
Pv1     3
PV2     4

按计数分组的特殊情况

2 个答案: