Question

我有下一个查询

SELECT id, type FROM clients WHERE 1 GROUP BY id, type

+----+------+
| id | type |
+------+----+
|  1 |    1 |
|  1 |    2 |
|  1 |    3 |
|  2 |    2 |
|  2 |    3 |
+----+------+

但是我想忽略id“1”，因为它有一个类型1，因此，在这种情况下，我只想拥有id“2”

任何人都可以帮助我，谢谢

Answer 1

您可以使用NOT EXISTS：

SELECT id, type 
FROM clients AS c1
WHERE NOT EXISTS (SELECT 1
                  FROM clients AS c2
                  WHERE c1.id = c2.id AND c2.type = 1)

<强>输出：

+----+------+
| id | type |
+----+------+
|  2 |    2 |
|  2 |    3 |
+----+------+

Answer 2

语法略有不同：

SELECT distinct id, type
FROM clients
WHERE id not in (select distinct id from clients where type=1)

如果行没有通过过滤器，则可以忽略结果组

2 个答案: