我通过AJAX传递查询并尝试在noty-master jquery插件中获取数据。
HTML
<!DOCTYPE html>
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<meta charset="utf-8">
<title>Using with Buttons</title>
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta name="description" content="demonstration of some noty capabilities">
<link href='http://fonts.googleapis.com/css?family=PT+Sans:regular,italic,bold,bolditalic&subset=latin,latin-ext,cyrillic' rel='stylesheet' type='text/css'>
<style type="text/css">
html {
height: 100%;
width: 100%;
}
body {
font-family: 'PT Sans', Tahoma, Arial, serif;
line-height: 13px
}
</style>
<link rel="stylesheet" type="text/css" href="buttons.css"/>
</head>
<body>
<div class="container">
<div id="customContainer"></div>
</div>
<script src="noty-master/demo/jquery-1.7.2.min.js"></script>
<!-- noty -->
<script type="text/javascript" src="packaged/jquery.noty.packaged.js"> </script>
<script type="text/javascript">
function display(){
//e.preventDefault();
datastring = '2016-02-19';
$.ajax({
url: "bootajax.php",
data: datastring,
type:"POST"
}).done(function(info) {
var data = jQuery.parseJSON(info);
console.log(info);
generate(data[0].fname, data[0].comment);
});
}
function generate(layout, name, comment) {
var n = noty({
text : name+' : '+comment,
type : 'alert',
dismissQueue: true,
layout : layout,
theme : 'defaultTheme',
buttons : [
{addClass: 'btn btn-primary', text: 'Comment', onClick: function ($noty) {
$noty.close();
noty({dismissQueue: true, force: true, layout: layout, theme: 'defaultTheme', text: 'You clicked "Comment" button', type: 'success'});
}
},
{addClass: 'btn btn-danger', text: 'Dismiss', onClick: function ($noty) {
$noty.close();
noty({dismissQueue: true, force: true, layout: layout, theme: 'defaultTheme', text: 'You clicked "Dismiss" button', type: 'error'});
}
}
]
});
console.log('html: ' + n.options.id);
}
function generateAll() {
generate('centerRight');
}
$(document).ready(function () {
generateAll();
display();
});
</script>
</body>
</html>
AJAX
<?php session_start();
$companydata = $_SESSION['company'];
$idCompany = $companydata['id'];
$fnameCompany = $companydata['fname'];
$lnameCompany = $companydata['lname'];
$password = $companydata['password'];
$dbhost = "localhost";
$dbusername = "root";
$dbpassword = "";
$dbname = "gym";
$time = date('Y-m-d');
$conn = mysqli_connect($dbhost, $dbusername, $dbpassword, $dbname) or die ("could not connect");
$sql = "SELECT * from inquiry where callback = '2016-02-19'";
$result = mysqli_query($conn, $sql);
$row = mysqli_fetch_all($result, MYSQLI_ASSOC);
echo json_encode($row);
?>
我使用过JSON并尝试传递数据,但其显示:
未捕获的错误,无法准备好属性&#39;选项&#39;未定义的
请帮忙。