Question

您好，这是我的代码，我想让它变得动态，请为我提供一个如何做的解决方案。

$start = strtotime($this->input->post('leave_from'));
$end = strtotime($this->input->post('leave_to'));
$days_between = ceil(abs($end - $start) / 86400 + 1);

if($this->input->post('leave_type') == 3){
    $days_between = 0.5;
}

我想让这个动态如何使用查询。

$q = "set leave_applications.days = '0.5' on leave_applications where leave_type = 3 "; 
$days_between = $this->leave_application_model->q_single($q);

不知道它是否正确但是显示错误

未知系统变量＆＃39;天＆＃39;设置leave_applications.days =＆＃39; 0.5＆＃39;上 leave_applications where leave_type = 3

帮我解决这个问题。感谢。

Answer 1

UPDATE `leave_applications` SET `days` = '0.5' WHERE `leave_type` = 3

如何在动态查询中创建静态值

1 个答案: