Question

我有一个像这样的numpy数组：

 n=   [['20015' '20013' '20044' '20001' '20002']
     ['20002' '20015' '20001' '20013' '20070']
     ['20044' '20013' '20015' '20001' '20002']
     ['20071' '20015' '20070' '20001' '20002']]

我希望将此列表打印成以下形式的文件：

20015, 20013, 20044, 20001, 20002
 20002, 20015, 20001, 20013, 20070

如何删除列表列表但仍保持组合在一起：我试过这个：

    f=open("myfile.txt, "w")
    n=clf.classes_[order[:, -5:]]
    print(n)
    str1=''.join(str(x) for x in n)
    print>>f, str1
    f.close()

但这再次将它们列入一个列表。

Answer 1

如果我理解正确，您只想打印问题中显示的元素。这应该有效：

with open("myfile.txt", "w") as f:
    for row in n:
        s = ', '.join(str(x) for x in row)
        f.write(s)
        f.write("\n")

Answer 2

这应该符合您的要求：

>>> n = [[20015, 20013, 20044, 20001, 20002],
     [20002, 20015, 20001, 20013, 20070],
     [20044, 20013, 20015, 20001, 20002],
     [20071, 20015, 20070, 20001, 20002]]
>>> with open('myfile.txt', 'w') as file:
    for row in n:
        print(*row, sep=', ', file=file)

>>>

证明它正常工作很简单：

>>> print(open('myfile.txt').read())
20015, 20013, 20044, 20001, 20002
20002, 20015, 20001, 20013, 20070
20044, 20013, 20015, 20001, 20002
20071, 20015, 20070, 20001, 20002

>>>

Answer 3

试试这个

text = '\n'.join(', '.join(ni) for ni in n)
with open('myfile.txt','w') as f:
    f.write(text)

如何将numpy数组以字符串形式写入文件？

3 个答案: