我有一个钙化器。它的工作正常例子在textbox1中输入10-5,在textbox2上显示结果。但我想计算更多。例如8-5 * 3-1这样。或7-2 + 3等。
怎么会这样?
这是我的代码
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
float ricxvi1, pasuxi;
int datvla;
private void button2_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + 7;
}
private void button1_Click(object sender, EventArgs e)
{
textBox1.Clear();
textBox1.Text = textBox1.Text + 0;
textBox2.Clear();
textBox2.Text = textBox2.Text + 0;
datvla = 0;
}
private void button6_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + 4;
}
private void button17_Click(object sender, EventArgs e)
{
ricxvi1 = ricxvi1 = float.Parse(textBox1.Text);
datvla = 1;
textBox1.Text += "-";
}
private void button10_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + 1;
}
private void button11_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + 2;
}
private void button12_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + 3;
}
private void mimateba_Click_1(object sender, EventArgs e)
{
ricxvi1 = float.Parse(textBox1.Text);
datvla = 2;
textBox1.Text += "+";
}
private void button7_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + 5;
}
private void button8_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + 6;
}
private void button5_Click(object sender, EventArgs e)
{
ricxvi1 = float.Parse(textBox1.Text);
datvla = 3;
textBox1.Text += "*";
}
private void button3_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + 8;
}
private void button4_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + 9;
}
private void button9_Click(object sender, EventArgs e)
{
ricxvi1 = float.Parse(textBox1.Text);
datvla = 4;
textBox1.Text += "/";
}
private void button14_Click(object sender, EventArgs e)
{
textBox1.Text = textBox1.Text + 0;
}
private void button16_Click_1(object sender, EventArgs e)
{
switch (datvla)
{
case 1:
pasuxi = ricxvi1 - float.Parse(textBox1.Text.Substring(textBox1.Text.Length - 1));
textBox2.Text = pasuxi.ToString();
break;
case 2:
pasuxi = ricxvi1 + float.Parse(textBox1.Text.Substring(textBox1.Text.Length - 1));
textBox2.Text = pasuxi.ToString();
break;
case 3:
pasuxi = ricxvi1 * float.Parse(textBox1.Text.Substring(textBox1.Text.Length - 1));
textBox2.Text = pasuxi.ToString();
break;
case 4:
pasuxi = ricxvi1 / float.Parse(textBox1.Text.Substring(textBox1.Text.Length - 1));
textBox2.Text = pasuxi.ToString();
break;
default:
break;
}
}
private void button15_Click(object sender, EventArgs e)
{
if (textBox1.Text == "0")
textBox1.Clear();
textBox1.Text = textBox1.Text + ".";
}
private void Form1_Load(object sender, EventArgs e)
{
}
}
答案 0 :(得分:0)
您必须构建一个解析器来理解完成的计算。正则表达式或手动解析非常困难,可能比使用解析器更难。
一个好的解析器是ANTLR,它也有一个ample grammar for a calculator。
答案 1 :(得分:0)
您最有可能想要创建一个方法,该方法接收输入的十进制值。比如下面的例子,你可以将输入的数字传递给方法。然后在方法调用的基础上调用计算方法。我的观点是,您不希望在UI中处理业务或数据逻辑,并且您有一个检查,清除和分配到文本框的常见任务,请找一个能够为您处理的方法。{ {3}}