Question

我正在尝试使用sql查询来订购数据，但是几天后我尝试了一切我没有想法如何做到这一点，所以，我做了这个查询

SELECT bm, SUM(CASE WHEN glasao = 'da' THEN 1 ELSE 0 END) + SUM(CASE WHEN glasao = 'ne' THEN 1 ELSE 0 END) AS [Ukupno u Bazi], SUM(CASE WHEN glasao = 'da' THEN 1 ELSE 0 END) 
                         AS Glasali, SUM(CASE WHEN glasao = 'ne' THEN 1 ELSE 0 END) AS [Nisu Glasali]
FROM            dbo.siguranglas
WHERE bm IN ('1','2','3','4','5','6','7','8','9','10','11','12','13','14','15','16','17','18','19','20','21','22','23','24','25','26','27','28','29','30','31','32','33','34','35','36') GROUP BY bm ORDER BY bm DESC

我得到了这个输出：

9   1   0   1
8   9   0   9
4   1   0   1
29  3   2   1
28  1   0   1
26  3   2   1
17  1   1   0
13  2   1   1

问题是，如何命令第一个columnt这样：

4   1   0   1
8   9   0   9
9   1   0   1
13  2   1   1
17  1   1   0
26  3   2   1
28  1   0   1
29  3   2   1

如果我能......还有一个问题，有人可以帮助我再做一件事吗，我希望所有这一切能够再增加一个专栏（Column3 *（column3 + column4））* 100 AS百分比

我尝试了很多东西并阅读了许多帖子但没有运气：P也许这不可能吗？

Answer 1

它们存储为文本值，因此按照这样的方式排序;对于数字排序，他们需要是数字：

 order by cast(bm as int) asc

Answer 2

您必须在排序

之前投放 BM 列

试试这个

        SELECT bm, SUM(CASE WHEN glasao = 'da' THEN 1 ELSE 0 END) + SUM(CASE WHEN glasao = 'ne' THEN 1 ELSE 0 END) AS [Ukupno u Bazi], SUM(CASE WHEN glasao = 'da' THEN 1 ELSE 0 END) 
               AS Glasali, SUM(CASE WHEN glasao = 'ne' THEN 1 ELSE 0 END) AS [Nisu Glasali]
        FROM  dbo.siguranglas
        WHERE bm IN ('1','2','3','4','5','6','7','8','9','10','11','12','13','14','15','16','17'        
                     '18','19','20','21','22','23','24','25','26','27','28','29','30','31','32',
                     '33','34','35','36')
        GROUP BY bm 
        ORDER BY cast(bm as int)DESC

Answer 3

根据给出的细节，我不认为Group by和order by中使用的列bm是整数列。首先，将其转换为整数列。

select *, (Glasali * (Glasali + Nisu Glasali)) * 100 as percent
from
(
SELECT bm, SUM(CASE WHEN glasao = 'da' THEN 1 ELSE 0 END) + SUM(CASE WHEN glasao = 'ne' THEN 1 ELSE 0 END) AS [Ukupno u Bazi], SUM(CASE WHEN glasao = 'da' THEN 1 ELSE 0 END) 
                         AS Glasali, SUM(CASE WHEN glasao = 'ne' THEN 1 ELSE 0 END) AS [Nisu Glasali]
FROM            dbo.siguranglas
WHERE bm IN ('1','2','3','4','5','6','7','8','9','10','11','12','13','14','15','16','17','18','19','20','21','22','23','24','25','26','27','28','29','30','31','32','33','34','35','36') GROUP BY bm ORDER BY bm DESC
) a 
order by cast(bm as integer)

顺便说一句，我不认为你的计算是计算百分比的正确方法。 CAST是一个oracle函数

Answer 4

当前结果，“bm”列似乎是一个字符串，对吧？

如果是这样，你需要在场上进行施法......

Answer 5

我认为这是SQL服务器。你的问题不是很清楚，但我想你的意思是：

WITH  preSum ( bm, Glasali, [Nisu Glasali] )
        AS (
             SELECT bm, SUM(CASE WHEN glasao = 'da' THEN 1
                                 ELSE 0
                            END),
                    SUM(CASE WHEN glasao = 'ne' THEN 1
                             ELSE 0
                        END)
             FROM   dbo.siguranglas
             WHERE  bm IN ( '1', '2', '3', '4', '5', '6', '7', '8', '9', '10',
                            '11', '12', '13', '14', '15', '16', '17', '18',
                            '19', '20', '21', '22', '23', '24', '25', '26',
                            '27', '28', '29', '30', '31', '32', '33', '34',
                            '35', '36' )
             GROUP BY bm
           )
  SELECT  bm, Glasali + [Nisu Glasali] AS [Ukupno u Bazi], Glasali,
          [Nisu Glasali],
          Glasali / ( Glasali + [Nisu Glasali] ) * 100 AS [percent]
  FROM    preSum
  ORDER BY cast(bm as int) DESC;

如何使用此查询进行SQL排序

5 个答案: