我编写了一个方法,可以生成一个数组的随机值,但我不知道如何生成另外两个因为它们最终只是相同的数字。 这是我写的,但它只是崩溃......
public void getRandomTopics() {
Random random = new Random();
int index = random.nextInt(group_topics.length);
randomOne = group_topics[index];
randomTwo = group_topics[index];
randomThree = group_topics[index];
if(randomOne.equals(randomTwo) || randomOne.equals(randomThree) || randomThree.equals(randomTwo)) {
isEqual = true;
}
while(isEqual = true){
randomOne = group_topics[index];
randomTwo = group_topics[index];
randomThree = group_topics[index];
}
topicOne = (TextView) findViewById(R.id.textView2);
topicOne.setText(randomOne);
topicTwo = (TextView) findViewById(R.id.textView3);
topicTwo.setText(randomTwo);
topicThree = (TextView) findViewById(R.id.textView4);
topicThree.setText(randomThree);
}
如果有人知道更简单的方法,那么非常感谢帮助:)
答案 0 :(得分:1)
创建3个不同的随机数:
int index1 = random.nextInt(group_topics.length);
int index2 = random.nextInt(group_topics.length);
int index3 = random.nextInt(group_topics.length);
现在使用这3个随机数而不是仅生成一次的index
。
randomOne = group_topics[index1];
randomTwo = group_topics[index2];
randomThree = group_topics[index3];