好的我有约会
date('Y-m-d H:i:s');
我们怎样才能让它像0秒前或x年x月x天x分钟x秒前一样?但是没有使用str_time(php 5.3.3)
编辑*
我的意思是some.date - time.now = some some some some some Some Some Some Some Some Some Some Some Some Some some
喜欢facebook或stackoverflow(更新。我的意思是那样。 - Adam Ramadhan 2 mins ago
编辑)
编辑* 有人说使用sktime吗?
2分钟前。
由于
Adam Ramadhan
答案 0 :(得分:2)
你应该尝试一下(看起来就像krike的答案,但这个是固定的!)
<?php
function ago($timestamp){
$difference = time() - $timestamp;
$periods = array("second", "minute", "hour", "day", "week", "month", "years", "decade");
$lengths = array("60","60","24","7","4.35","12","10");
for($j = 0; $difference >= $lengths[$j]; $j++)
$difference /= $lengths[$j];
$difference = round($difference);
if($difference != 1) $periods[$j].= "s";
$text = "$difference $periods[$j] ago";
return $text;
}
?>
这样做---
echo ago($timeofthethingyouwant);
请记住这适用于这种时间格式----
time(); //Or it looks like this 1299951275!
这是肯定的,它是伟大而轻量级的脚本!欲了解更多信息,请访问此链接 -
希望它有效!
答案 1 :(得分:1)
为什么不从30
的输出中减去time()
?
date('Y-m-d H:i:s',time()-30);
time()
返回以纪元为单位的秒数测量的当前时间,因此从中减去30
给出时间30
秒前的时间戳
答案 2 :(得分:1)
function nicetime($fromDate, $toDate = NULL, $precision = -1, $separator = ', ', $divisors = NULL) {
if ( is_null( $toDate ) ) {
$toDate = $this->date_get('Asia/Jakarta');
}
// Determine the difference between the largest and smallest date
$dates = array(strtotime($fromDate), strtotime($toDate));
$difference = max($dates) - min($dates);
// Return the formatted interval
return $this->format_interval($difference, $precision, $separator, $divisors);
}
/**
* Formats any number of seconds into a readable string
*
* @param int Seconds to format
* @param string Seperator to use between divisors
* @param int Number of divisors to return, ie (3) gives '1 Year, 3 Days, 9 Hours' whereas (2) gives '1 Year, 3 Days'
* @param array Set of Name => Seconds pairs to use as divisors, ie array('Year' => 31536000)
* @return string Formatted interval
*/
function format_interval($seconds, $precision = -1, $separator = ', ', $divisors = NULL)
{
// Default set of divisors to use
if(!isset($divisors)) {
$divisors = Array(
'Year' => 31536000,
'Month' => 2628000,
'Day' => 86400,
'Hour' => 3600,
'Minute' => 60,
'Second' => 1);
}
arsort($divisors);
// Iterate over each divisor
foreach($divisors as $name => $divisor)
{
// If there is at least 1 of thie divisor's time period
if($value = floor($seconds / $divisor)) {
// Add the formatted value - divisor pair to the output array.
// Omits the plural for a singular value.
if($value == 1)
$out[] = "$value $name";
else
$out[] = "$value {$name}s";
// Stop looping if we've hit the precision limit
if(--$precision == 0)
break;
}
// Strip this divisor from the total seconds
$seconds %= $divisor;
}
// FIX
if (!isset($out)) {
$out[] = "0" . $name;
}
var_dump($out);
// Join the value - divisor pairs with $separator between each element
return implode($separator, $out);
}
答案 3 :(得分:1)
我在google上搜索时发现了以下功能,我测试了代码,看起来效果很好。
function ago($timestamp){
$difference = time() - $timestamp;
$periods = array("second", "minute", "hour", "day", "week", "month", "years", "decade");
$lengths = array("60","60","24","7","4.35","12","10");
for($j = 0; $difference >= $lengths[$j]; $j++)
$difference /= $lengths[$j];
$difference = round($difference);
if($difference != 1) $periods[$j].= "s";
$text = "$difference $periods[$j] ago";
return $text;
}
然后你会将其称为
echo ago($time);
答案 4 :(得分:0)
相当简单 - 您需要开始和当前时间戳。例如,要查看从今晚开始日期(2010年8月22日太平洋标准时间晚上9点)过去的分钟数:
$start = strtotime('8/22/2010 9pm');
printf('%d minutes ago', (time() - $start) / 60);
// My Output: 36 minutes ago. Will vary, depending on the current time/zone.
60分数是得分。几秒钟就没有分裂了。数小时,数天,数年等使用不同的除数。以下解决方案具有用于格式化时间戳的示例函数: