Question

我正在尝试创建一个PHP函数，我使用以下格式输入$date变量：03/09/2016 - 12:02。

我创建了一个函数来将这个日期/时间变量转换为一个字符串，表示$date变量是x天和小时之前。

功能：

$date = $r->date;

                function nicetime($date)
                {
                    if(empty($date)) {
                        return "Geen datum gevonden.";
                    }

                    $periods         = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
                    $lengths         = array("60","60","24","7","4.35","12","10");

                    ini_set('date.timezone', 'Europe/Berlin');
                    $now             = time('Y-m-d H:i:s');
                    $unix_date       = $date;

                       // check validity of date
                    if(empty($unix_date)) {    
                        return "Error.";
                    }

                    // is it future date or past date
                    if($now > $unix_date) {    
                        $difference     = $now - $unix_date;
                        $tense         = "ago";

                    } else {
                        $difference     = $unix_date - $now;
                        $tense         = "from now";
                    }

                    for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
                        $difference /= $lengths[$j];
                    }

                    $difference = round($difference);

                    if($difference != 1) {
                        $periods[$j].= "s";
                    }

                    return "$difference $periods[$j] {$tense}";
                }

                $postdate = nicetime($date);

所以我使用$date来插入日期。 $postdate的结果是47年前。有人知道我做错了什么吗？因为我不应该在47年前得到。

Answer 1

因此，让我们将您的工作分成3个步骤：

第1步：分叉时间和日期。然后使用long function获取strtotime()时间

第2步：从long获取当前time()时间功能

第3步：现在 - Unix日期

<?php
    $date = $r->date;

        function nicetime($date)
        {
            if(empty($date)) {
                return "Geen datum gevonden.";
            }
            $r1 = split('/', $date);
            $day = $r1[0]; 
            $month = $r1[1]; 
            $year = split(' ', $r1[2]);
            $year = $year[0];
            $r1 = split('-', $date);

            $periods         = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
            $lengths         = array("60","60","24","7","4.35","12","10");

            ini_set('date.timezone', 'Europe/Berlin');

            $now             = time();
            $unix_date       = strtotime($month.'/'.$day.'/'.$year.' '. $r1[1])."</br>";;

               // check validity of date
            if(empty($unix_date)) {    
                return "Error.";
            }

            // is it future date or past date
            if($now > $unix_date) {    
                $difference     = $now - $unix_date;
                $tense         = "ago";

            } else {
                $difference     = $unix_date - $now;
                $tense         = "from now";
            }

            for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
                $difference /= $lengths[$j];
            }

            $difference = round($difference);

            if($difference != 1) {
                $periods[$j].= "s";
            }

            return "$difference $periods[$j] {$tense}";
        }

        $postdate = nicetime($date); // 2 days ago
        echo $postdate;
?>

顺便说一句，你做得很好。

更新：使用循环到此函数时，请确保将函数包含在条件块中：

   if (!function_exists('nicetime')) {
    // ... proceed to declare your function
}

日期字符串到时间格式（'时间'之前）

1 个答案: