我试图从选择字段中排除正在编辑的当前对象,以从同一模型中选择父对象。例如:
from django import forms
from django.contrib import admin
class RelationForm(forms.ModelForm):
parent = forms.ModelChoiceField(queryset=Ingredient.objects.exclude(id=current_ingredient_id))
def save(self, commit=True):
parent = self.cleaned_data.get('parent', None)
# ...do something with extra_field here...
return super(RelationForm, self).save(commit=commit)
class Meta:
model = IngredientRelations
exclude = ['description']
@admin.register(Ingredient)
class IngredientAdmin(admin.ModelAdmin):
form = RelationForm
fieldsets = (
(None, {
'fields': ('name', 'slug', 'description', 'parent',),
}),
)
困难来自于正在编辑当前对象,然后在RelationForm中为查询集参数获取其主键。
我尝试在IngredientAdmin中使用ModelAdmin.formfield_for_foreignkey和ModelAdmin.formfield_for_choice_field但没有运气。
有什么想法吗?
答案 0 :(得分:1)
执行此操作的规范方法是使用当前编辑的实例ID更新queryset
方法中的__init__
。
class RelationForm(forms.ModelForm):
def __init__(self, *args, **kwargs):
super(RelationForm, self).__init__(*args, **kwargs)
if self.instance.id:
self.fields['parent'].queryset = Ingredient.objects.exclude(id=self.instance.id)
class Meta:
model = IngredientRelations
exclude = ['description']