Question

关于将文本文件中的值组合到单个变量并打印它的问题。

我可以给出的一个例子是.txt文件，例如：

School, 234
School, 543

我想知道将两所学校合并为一个变量“学校”的必要步骤，其值为777.

我知道我们需要打开.txt文件进行读取，然后用.split（“，”）方法拆分它。

代码示例：

schoolPopulation = open("SchoolPopulation.txt", "r")
for line in schoolPopulation:
    line = line.split(",")

有人可以告诉我如何解决这个问题吗？

Answer 1

Python拥有丰富的标准库，您可以在其中找到许多典型任务的类。 Counter是您目前所需要的：

from collections import Counter
c = Counter()


with open('SchoolPopulation.txt', 'r') as fh:
    for line in fh:
        name, val = line.split(',')
        c[name] += int(val)

print(c)

Answer 2

这样的东西？

schoolPopulation = open("SchoolPopulation.txt", "r")
results = {}
for line in schoolPopulation:
    parts = line.split(",")
    name = parts[0].lower()
    val = int(parts[1])
    if name in results:
        results[name] += val
    else:
        results[name] = val
print(results)
schoolPopulation.close()

您还可以使用defaultdict和with关键字。

from collections import defaultdict

with open("SchoolPopulation.txt", "r") as schoolPopulation:
    results = defaultdict(int)
    for line in schoolPopulation:
        parts = line.split(",")
        name = parts[0].lower()
        val = int(parts[1])
        results[name] += val

print(results)

如果您想要很好地显示结果，可以执行类似

的操作

for key in results:
    print("%s: %d" % (key, results[key]))

Answer 3

school = population = prev = ''
pop_count = 0
with open('SchoolPopulation.txt', 'r') as infile:
     for line in infile:
          line = line.split(',')
          school = line[0]
          population = int(line[1])
          if school == prev or prev == '':
               pop_count += line[1]
          else:
               pass #do something else here
          prev = school

Python 3.X将.txt文件中的类似行组合在一起

3 个答案: