Question

我正在写一张有52张牌的牌组。一切都很完美，但我无法弄清楚如何在不使用java中的任何库并使用java内置的排序方法的情况下对其进行混洗。这是我的代码。我一直试图找出一段时间的东西，到目前为止，我无法做到。

String [] deck2=new String [52];
String[] deck=new String [52];
String suits[]={"Spades","Hearts","Diamonds","Clubs"};
String rank[]={"2","3","4","5","6","7","8","9","10","Jack","King","Queen","Ace"};

for(int i=0;i<deck.length;i++){
    deck[i]=rank[i%13]+" "+"of "+suits[i/13];
    deck2[i]=deck[i];
    System.out.println(deck[i]);

}}}

Answer 1

for (int i = 0; i < 500; i++) {
    int from = (int) (Math.random() * array.length); //The place to get the first from
    int to = (int) (Math.random() * array.length); // The place to get the second from
    String perm = array[from]; // Store the "from" value
    array[from] = array[to]; // Set the first value to the second
    array[to] = perm; // Set the second value to the first
}

我不知道，为什么你不想使用java内置库，他们是有原因的。

要创建一个没有任何内置方法的随机数很难。很久以前我找到了一种方法，使用float，并使其溢出

float random = 1 << 32 + 1256224; //Have a random number here, it doesn't matter

我没有测试过，这可能不起作用。

float random = 1 << 32 + 1256224;
String [] deck2=new String [52];
String[] deck=new String [52];
String suits[]={"Spades","Hearts","Diamonds","Clubs"};
String rank[]={"2","3","4","5","6","7","8","9","10","Jack","King","Queen","Ace"};

for(int i=0;i<deck.length;i++){
    deck[i]=rank[i%13]+" "+"of "+suits[i/13];
    deck2[i]=deck[i];
    System.out.println(deck[i]);

}
for (int i = 0; i < 500; i++) {
    int from = (int) (Math.random() * array.length); //The place to get the first from
    int to = (int) (Math.random() * array.length); // The place to get the second from
    String perm = array[from]; // Store the "from" value
    array[from] = array[to]; // Set the first value to the second
    array[to] = perm; // Set the second value to the first
}

}}

Answer 2

当然有可能。毕竟，一个库只不过是一些代码，你可以写自己。您必须编写自己的随机数生成器。这是一个简单的例子：

private static long x = System.currentTimeMillis();

public static long rndNumber() {
    x ^= (x << 21);
    x ^= (x >>> 35);
    x ^= (x << 4);
    return x < 0 ? -x : x;
}

public static void shuffle(int a[]) {
    for (int i = a.length - 1; i > 0; i--) {
        int pos = (int) (rndNumber() % a.length);
        int temp = a[i];
        a[i] = a[pos];
        a[pos] = temp;
    }
}

public static void main(String[] args) {
    int a[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
    System.out.println(Arrays.toString(a));
    shuffle(a);
    System.out.println(Arrays.toString(a));
}

如何在不使用库和排序方法的情况下混洗String数组？

2 个答案: